All categories

3 years ago

Determine the number of solutions that exist to the equation?

Mathematics

1 answer:

IceJOKER [234]3 years ago

6 0

Many when you solve it it works out perfectly.

You might be interested in

the ratio of the circumferences of two circles is 2:3. If the large circle has a radius of 39 cm, what is the radiusof the small

Orlov [11]

C1/C2 = 2/3

2pi r1 / 2pi r2 = r1/r2 = 2/3

r1/39 = 2/3

r1 = 39*2/3 = 26

So, your answer is 26cm

8 0

3 years ago

Read 2 more answers

in the diagram, AE is tangent to the circle at point a and secant DE intersects the circle at point C and D. the iines intersect

AlexFokin [52]

Recall the secant-tangent theorem, and you have
EA^2 = EC*CD
12^2 = 8*(x+10)
and now ED = EC+CD = 8+x+10

I suspect a typo somewhere in the murk above

8 0

1 year ago

Sin α = 21/29, α lies in quadrant II, and cos β = 15/17, β lies in quadrant I Find sin (α - β).

Sever21 [200]

$\sin(\alpha-\beta)=\sin\alpha\cos\beta-\cos\alpha\sin\beta$

$\sin\alpha=\dfrac{21}{29}\implies \cos^2\alpha=1-\sin^2\alpha=\dfrac{400}{841}$

Since $\alpha$ lies in quadrant II, we have $\cos\alpha$ , so

$\cos\alpha=-\sqrt{\dfrac{400}{841}}=-\dfrac{20}{29}$

$\cos\beta=\dfrac{15}{17}\implies\sin^2\beta=1-\cos^2\beta=\dfrac{64}{289}$

$\beta$ lies in quadrant I, so $\sin\beta>0$ and

$\sin\beta=\sqrt{\dfrac{64}{289}}=\dfrac8{17}$

So

$\sin(\alpha-\beta)=\dfrac{21}{29}\dfrac{15}{17}-\left(-\dfrac{20}{29}\right)\dfrac8{17}=\dfrac{475}{493}$

8 0

3 years ago

The regular price of a space invader game is 52$ but it is on sale.the discount is 13$ what percent discount is this?

Mama L [17]

The answer would be 25%

3 0

3 years ago

Triangle ABC is equilateral. Find the height of BD

RideAnS [48]

Since ABC is equilateral, all 3 sides have equal length. side AC is 8 units since side BC is 8 units.

Line BD is placed in the middle, making D the midpoint of side AC.

knowing this information we can determine that the length of DC is 4 units (half of AC)

since triangle BDC is a right triangle, we can use the side lengths in the pythagorean theorem to find the length of BD

a²+b²=c² where a & b = legs of triangle , and c= hypotenuse (longest side)

we are given the hypotenuse and found one leg so we can plug our values into the equation to find the third

4² + b²= 8²

16 + b² = 64

b² = 48

b = $\sqrt{48}$

b= 4√3 or about 6.928 units

hope this helped

3 0

3 years ago