The pH of the solution : 12
<h3>Further explanation</h3>
Reaction
HCOOH + NaOH ⇒ HCOONa + H₂O
mol HCOOH =
mol NaOH =
Mol NaOH>mol HCOOH ⇒ at the end of the reaction there will be a strong base remains from mol NaOH, so that the pH is determined from [OH⁻]
ICE method :
HCOOH + NaOH ⇒ HCOONa + H₂O
4 5
4 4 4 4
0 1 1 1
Concentration of [OH⁻] from NaOH :
pOH=-log[OH⁻]
pOH=-log 10⁻²=2
pH+pOH=14
pH=14-2=12
longitudinal wave.... is the right answer
<h2>
<em># Good morning</em></h2>
The coefficients are the whole numbers written before the substances to obey the Law of Conservation of Mass, or more specifically, the Law of Definite Proportions. You have to make sure that the number of each substance before and after the reaction must be the same. Thus, the given reaction is already balanced. <em>The coefficient for each substance in the reaction is 1</em>. When no coefficient is written, it is by default equal to 1.
There are 6.02 × 10²³ formula units of CaCl2 in 111 g CaCl2. Details about formula units can be found below.
<h3>What is a formula unit?</h3>
Formula unit refers to the empirical formula of an ionic compound for use in stoichiometric calculations.
According to this question, there are 111g of CaCl2. The formula units can be calculated by multiplying the number of moles by Avogadro's number.
no of moles in CaCl2 = 111g ÷ 111g/mol = 1mol
Formula units of CaCl2 = 1mol × 6.02 × 10²³ = 6.02 × 10²³ formula units.
Therefore, there are 6.02 × 10²³ formula units of CaCl2 in 111 g CaCl2.
Learn more about formula units at: brainly.com/question/21494857
#SPJ1