Answer:
200 g C₆H₁₂O₆
General Formulas and Concepts:
<u>Chemistry - Solutions</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Molarity = moles of solute / liters of solution
Explanation:
<u>Step 1: Define</u>
1 M C₆H₁₂O₆
1 L of solution
<u>Step 2: Identify Conversions</u>
Molar Mass of C - 12.01 g/mol
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar mass of C₆H₁₂O₆ - 6(12.01) + 12(1.01) + 6(16.00) = 180.18 g/mol
<u>Step 3: Find moles of solute</u>
1 M C₆H₁₂O₆ = x mol C₆H₁₂O₆ / 1 L
x = 1 mol C₆H₁₂O₆
<u>Step 4: Convert</u>
<u />
= 180.18 g C₆H₁₂O₆
<u>Step 5: Check</u>
<em>We are given 1 sig figs. Follow sig fig rules and round.</em>
180.18 g C₆H₁₂O₆ ≈ 200 g C₆H₁₂O₆
Answer:
the charge is -1
Explanation:
because the charge of proton is +and electron -
charge = +49 +(-50)
= -1
Disagree, because they can come together to form a compound element. Hope it helped!
Answer:
thx for the points but I didn't understand
Below are I think the data for this problem:
Given the following data:
<span>Ca (s) + 2 C (graphite) → CaC2 (s) ∆H = -62.8 kJ </span>
<span>Ca (s) + ½ O¬2 (g) → CaO (s) ∆H = -635.5 kJ </span>
<span>CaO (s) + H2O (l) → Ca(OH)2 (aq) ∆H = -653.1 kJ </span>
<span>C2H2 (g) + 5/2 O¬2 (g) → 2 CO2 (g) + H2O (l) ∆H = -1300 kJ </span>
<span>C (graphite) + O¬2 (g) → CO2 (g) ∆H = -393.51 kJ
</span>
Below is the answer:
CaC2 (s) + 2 H2O (l) → Ca(OH)2 (aq) + C2H2 (g)
<span>So what you do is: </span>
<span>Times the first equation by -1 Second by 1 Third By 1 Fourth by -1 and Fifth by 2 </span>
<span>So This gives us: </span>
<span>1.CaC2--> Ca+2C </span>
<span>2.Ca+1/2O2-->CaO </span>
<span>3.CaO+H2O-->Ca(OH)2 </span>
<span>4.2CO2+H2O-->C2H2+5/2O2 </span>
<span>5.2C+202-->2CO2 </span>
<span>Now you cancel out like terms on either sides of the equation and you end up with </span>
<span>CaC2 (s) + 2 H2O (l) → Ca(OH)2 (aq) + C2H2 (g) Just what you wanted </span>
<span>So to calculate ∆H: </span>
<span>62.8-635.5-653.1+1300-787.02= -712.82</span>
