Please help with math !!!!

A study was done to determine the average number of homes that a homeowner owns in his or her lifetime. For the 50 homeowners su

ipn [44]

Answer:

The 95% confidence interval for the true average number of homes that a person owns in his or her lifetime is (4,6.2).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So

df = 50 - 1 = 49

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 49 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.0096

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.0096\frac{3.8}{\sqrt{50}} = 1.1$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 5.1 - 1.1 = 4

The upper end of the interval is the sample mean added to M. So it is 5.1 + 1.1 = 6.2.

The 95% confidence interval for the true average number of homes that a person owns in his or her lifetime is (4,6.2).

7 0

2 years ago

Can you help me out on this one

Bad White [126]

Answer:

I think the answer is C if I'm wrong sorry its been two years since i last learnt this

Step-by-step explanation:

6 0

3 years ago

Filipo is building a rectangular sandbox . The length of the sandbox is 1 foot longer than twice the width of the sandbox .the p

Alla [95]

Answer:

Part A : D.) $2w + 2(2w+ 1) = 29$

Part B : Length of the sandbox is 10 feet.

Step-by-step explanation:

Given,

Perimeter = 29 ft

We need to find the equation for the perimeter and also the length of the sandbox.

Solution,

Let the width of the sandbox be 'w'.

Now as per question said;

The length of the sandbox is 1 foot longer than twice the width of the sandbox.

So we can say that;

Length = $2w+1$

Now we know that the perimeter is equal to the sum of twice of length and width.

framing in equation form, we get;

Perimeter = $2(2w+1)+2w$

we have given the perimeter, so on substituting the value, we get;

$29=2(2w+1)+2w$

Hence The equation used to find the width is $29=2(2w+1)+2w$ .

Now we solve for 'w'.

Applying distributive property, we get;

$4w+2+2w=29\\\\6w+2=29$

Subtracting both side by '2' we get

$6w+2-2=29-2\\\\6w=27$

Dividing both side by 6 we get;

$\frac{6w}{6}=\frac{27}{6}\\\\w=4.5\ ft$

Width of the sandbox = 4.5 ft

Length of the sandbox = $2w+1=2\times4.5 +1 = 9+1=10\ ft$

Hence Length of the sandbox is 10 feet.

3 0

3 years ago

Simplify the expression:<br><br> –3(9 − x) =

steposvetlana [31]

Answer:

Expand $-3(9-x): -27 + 3x$

Step-by-step explanation:

$-3(9-x)$

Apply the distributive law: $a(b-c)=ab-ac$

$a = -3, b=9, c=x$

$=-3*9-(-3)x$

Apply minus - plus rules:

$-(-a)=a$

$= -3*9+3x$

Multiply the numbers: $3 * 9 = 27$

$=-27+3x$

Hope this helps! If so, may I get Brainliest and a Thanks?

Thank you, have a good one! =)

6 0

3 years ago

Simplify (6x2 + 11x − 3) + (2x2 − 17x − 4).

d1i1m1o1n [39]

Answer:

B. 8x^2-6x-7

Step-by-step explanation:

All you have to do is combine the like terms.

Like terms are the terms that have the same variable and same exponent.

The like terms in this equation are 6x^2 and 2x^2, 11x and -17x, and -3 and -4.

When you add 6x^2 and 2x^2, you get 8x^2

When you add 11x and -17x, you get -6x

When you add -3 and -4, you get -7.

Putting these all in order, your answer is

8x^2 - 6x - 7

8 0

3 years ago