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3 years ago

8

Please help with math !!!!

1 answer:

Elena L [17]3 years ago

8 0

If you put a better pic I will help you

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If you had to put up a fence around a circular baseball field, you would need to know the _________?

laila [671]

You would need to know the diameter of the field, and from that, you need to get the circumference of the field by using the formula C = πd.

By getting the circumference, you can therefore determine the perimeter/length of the fence you will need to enclose it.

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3 years ago

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Reduce the Fractions 15/9to its Lowest Terms

KatRina [158]

$\large\bf{\red{ \implies}} \tt \: \cancel\frac{15}{9} \\$

$\large\bf{\red{ \implies}} \tt \: \frac{5}{3} \\$

Decimal Form - 1.6667

6 0

3 years ago

A computer repair technician charges $35 for each job plus $21 per hour of labor and 110% of the cost of parts. The total charge

Novay_Z [31]

Answer:

The cost of parts was $65.

Step-by-step explanation:

Let the cost of parts = x

35 + 21(3) + 1.10x = 169.50

98 + 1.10x = 169.50

71.50 = 1.10x

71.50/1.10 = 65

7 0

3 years ago

Factor completely 3ab − 5ax + 9b − 15x.

victus00 [196]

<span>(3b - 5x)(a +3) is the answer

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3 years ago

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A restaurant serves custom-made omelets, where guests select meat, cheese, and vegetables to be added to their omelet. There are

FrozenT [24]

Answer:

15 possible combinations

Step-by-step explanation:

Given

$Vegetables = 6$

$Selection = 2$

Required

Determine the possible number of combinations

The question emphasizes on "selection" which means "combination".

So; To answer this question, we apply the following combination formula:

$^nC_r = \frac{n!}{(n-r)r!}$

In this case:

$n = 6$

$r = 2$

The formula becomes:

$^6C_2 = \frac{6!}{(6-2)!2!}$

$^6C_2 = \frac{6!}{4!2!}$

$^6C_2 = \frac{6*5*4!}{4!2*1}$

$^6C_2 = \frac{6*5}{2}$

$^6C_2 = \frac{30}{2}$

$^6C_2 = 15$

<em>Hence, there are 15 possible combinations</em>

7 0

3 years ago