Answer: 1 -2ax²+2x-ax
Step-by-step explanation:
Hi, to answer this question we have to apply the next formula:
Area of a rectangle: length x width
Replacing with the values given:
A = (2x+1) (1-ax)
A = [2x(1)] + [2x(-ax)] +[ 1(1)]+ [1 (-ax)]
A = 2x- 2ax² +1- ax
A = 1 -2ax²+2x-ax
In conclusion, the correct option is 1 -2ax²+2x-ax
Feel free to ask for more if needed or if you did not understand something.
Answer:
∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and lies between AB and KM and BK is the transversal line)
m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)
Step-by-step explanation:
Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK
TO prove: KM ║AB
Now, As given in figure 1,
In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)
Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)
Now ∵ ∠MBK = ∠BKM
and ∠ABK = ∠KBM
∴ ∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)
Hence proved.
Answer:
I believe the answer is d
Answer:
14+21
Step-by-step explanation:
because, 14+21 =35
21 is 7 more bigger than 14
Since the total measure of all the angles of a triangle is always 180, solve for x with the equation: 3x+1+2x-3+9x=180. x=13. Now plug in x and look for the smallest one, which will be B. 23 degrees.