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hram777 [196]
3 years ago
9

Plot the data for the functions f(x) and g(x) on a grid

Mathematics
1 answer:
wariber [46]3 years ago
7 0
The graph (by some miracle) has been uploaded for you. It is just about the first time I've done this sort of thing, and I've answered nearly 800 questions. 

The first thing you have to do is study the graph. The two functions are
f(x) = 4^x That's the curved graph. (in red)
g(x) = x + 4. That's the straight line. (in blue)

You know that the first one is not a linear relationship because the x values go from integer values -2 to 2 (including 0). The y values are a bit different. They go from 1/16 to 16 with those integer values. So you could try y = 4^(-x). It doesn't work, but you could try it. It gives the table numbers for y in the reverse order that the table you are given goes. For x you get -2 -1 0 1 2 and for y you would get 16 4 1 1/4 1/16.

You could try y = (1/4)^x
For this try, you would get x = -2 -1 0 1 2 and for y = 16 4 0 1/4 and 1/16 
but that doesn't work either.

You could try until you get y = 4^x which does work.

g(x) is a lot easier to deal with. It looks better behaved. as x goes up, so does y. You will find that the y values obey y = x + 4. You could try other lines, but that one works. Many times it's just a guess

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Urgently need help!!! I will mark the best answer as BRAINLIEST!!!!!
Lady bird [3.3K]

C. 16.4

Step-by-step explanation:

The formula to apply here is;

A=P(1+r/n) ^nt where

A=final amount

P=starting amount

r=rate of interest annually

n=number of compounding per year

t=time in years

Given ; P=$500, A=$750 , r=2.5%=0.025 , t=?,n=1

Substitute values;

A=P(1+r/n)^nt

$750=$500(1+0.025)^t

750=500(1.025)^t

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Compound interest formula :brainly.com/question/12148233

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We conclude that the line joining the mid-point of two sides of a triangle is equal to half the length of the third side. The converse of this theorem states: If a line is drawn through the mid-point of a side of a triangle parallel to the second side, it will bisect the third side.

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