3 years ago

Find the value of f(-2)

1 answer:

3 0

$f(x)=\left\{\begin{array}{ccc}x^2&if\ x\leq1\\1&if\ 1 \ \textless \ x \leq2\\2-x&if\ 3 \ \textless \ x \leq6\end{array}\right\\\\f(-2)=?\\\\-2\leq1\ therefore\ f(x)=x^2\\\\subtitute\\\\f(-2)=(-2)^2=4$

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