Answer:
The relation 
is explained below.
Step-by-step explanation:
P(x, y) is a point on the circle. Q is the origin. Join PQ.
PQ is the radius.
Therefore, PQ = r
Draw PS perpendicular to the x-axis.
Now, ΔPQS is a right triangle.
By Pythagoros theorem,
Answer:
√(p²-4q)
Step-by-step explanation:
Using the Quadratic Formula, we can say that
x = ( -p ± √(p²-4(1)(q))) / 2(1) with the 1 representing the coefficient of x². Simplifying, we get
x = ( -p ± √(p²-4q)) / 2
The roots of the function are therefore at
x = ( -p + √(p²-4q)) / 2 and x = ( -p - √(p²-4q)) / 2. The difference of the roots is thus
( -p + √(p²-4q)) / 2 - ( ( -p - √(p²-4q)) / 2)
= 0 + 2 √(p²-4q)/2
= √(p²-4q)
Answer:
-6
Step-by-step explanation:
input the numbers
do the problem in the parentheses first
-6-12 = -18
now it becomes
simplify and you'll get
-6
this is because -18 ÷ 3 =
-6
Answer:
x>5
Step-by-step explanation:
30 < 6x
Divide both sides by 6,
5 < x => x>5
The corresponding parts that are congruent are (a) AB and DE
<h3>How to determine the congruent parts?</h3>
The statement ΔABC ≅ ΔDEF means that the triangles ABC and DEF are congruent.
This implies that the following points are corresponding points:
A and D; B and E; C and F
When two corresponding points are joined together, the congruent parts are:
AB and DE, AC and DF, BC and EF
Hence, the corresponding parts that are congruent are (a) AB and DE
Read more about congruent triangles at:
brainly.com/question/1675117
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