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3 years ago

Write the equation in slope-intercept form for a line which points go through (-2,3), parallel to x=o

Mathematics

1 answer:

castortr0y [4]3 years ago

7 0

Answer:

x = -2

Step-by-step explanation:

Line x = 0 is parallel to y-axis

Line parallel to given line is also parallel to y-axis. It passes through point (-2, 3), so its equation is:

x = -2

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Ivanna says that 2 and 4/9 is equal to 9 divided by 22 is she correct

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9 divided by 22 is 9/22

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Find (f −1)'(a).<br><br> f(x) = 4 + x2 + tan(πx/2), −1 < x < 1, a = 4

Vinvika [58]

Answer:

The solution is $(f^{-1})'(a) = \frac{2}{\pi }$

Step-by-step explanation:

From the question we are told that

The function is $f(x) = 4 + x^2 + tan [\frac{ \pi x}{2} ]$ , -1 < x < 1 a = 4

Here we are told find $(f^{-1}) (a)$

Let equate

$f(x) = a$

$4 + x^2 + tan[\frac{\pi x }{2} ] = 4$

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For the equation above to be valid x must be equal to 0

Now when x = 0

$f(0) = 4+0^2 + tan [\frac{ \pi * 0}{2} ]$

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=> $0 = f^{-1} (4)$

Differentiating f(x)

$f(x)' = 0 + 2x + sec^2 (\frac{\pi x}{2} )\cdot \frac{\pi}{2}$

Now

since $0 = f^{-1} (4)$

We have

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3 years ago

The image below shows 2 complementary angles.

oksian1 [2.3K]

Answer:

a)(x + 3) + (2x - 3) = 90

b)(x + 3) + (2x - 3) = 90

-3 -3

-------------------------------

x + (2x-3) = 87

+3 +3

------------------------------

x + 2x = 90

Simpify: x + 2x = 3x

3x/3 = 3

90/3 = 30

x = 30º

c)(30 + 3) = 33º for angle A

(2x30-3)= 57º for angle B

Step-by-step explanation:

Set them equal to 90º because complementary means 2 angles that = 90º

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