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snow_tiger [21]
3 years ago
9

A lottery consists of one $2000 winner, three $500 winners, and ten $100 winners. a total of 1000 tickets are sold for $10 each.

find the expected winnings for a person purchasing one ticket.
Mathematics
1 answer:
Semenov [28]3 years ago
7 0

Answer: -5.5

 

WOKINGS

Given that the lottery has the following number of winners:

One $2000 winner

Three $500 winners

Ten $100 winners

 

Also Given,

A total of 1000 tickets are sold

Each ticket costs $10

 

The expected winning for a person purchasing one ticket is the sum of the products of the gain/loss and their corresponding probability.

 

There is one $2000 winner

There are 1000 tickets

The probability of winning $2000

= 1/1000

= .001

There are three $500 winners

There are 1000 tickets

The probability of winning $500

= 3/1000

= .003

 


There are ten $100 winners

There are 1000 tickets

The probability of winning $100

= 10/1000

= .01

 

Since each ticket costs $10

Everyone who buys a ticket automatically loses $10.

Therefore, the probability of losing $10 is 1

 

Now to calculate the expected winning for a person purchasing one ticket

= 2000(.001) + 500(.003) + 100(.01) – 10(1)

= 2 + 1.5 + 1 – 10

= -5.5

 

The expected winning is -5.5. This implies that a person playing this lottery can expect to lose $5.50 for every one ticket that they purchase. 

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HELP PLEASE!!! CLUELESS
statuscvo [17]
-3-8X≥9

Add 3 on both sides.

-8X≥12

Divide by negative 8 and flip the sign.

X≤-1.5

There isn't a number behind five, so I would just keep as is.

I hope this helps!
~kaikers
5 0
3 years ago
-1/3 + (-7/4)<br> pls help
djverab [1.8K]

Answer:

  -25            

 ——— = -2.08333

    12  

Step-by-step explanation:

Step  1  :

           7

Simplify   —

           4

Equation at the end of step  1  :

       1           7

 (0 -  —) +  (0 -  —)

       3           4

Step  2  :

           1

Simplify   —

           3

Equation at the end of step  2  :

       1     -7

 (0 -  —) +  ——

       3     4

Step  3  :

Calculating the Least Common Multiple :

3.1    Find the Least Common Multiple

     The left denominator is :       3

     The right denominator is :       4

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

3 1 0 1

2 0 2 2

Product of all

Prime Factors  3 4 12

     Least Common Multiple:

     12

Calculating Multipliers :

3.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 4

  Right_M = L.C.M / R_Deno = 3

Making Equivalent Fractions :

3.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      -1 • 4

  ——————————————————  =   ——————

        L.C.M               12  

  R. Mult. • R. Num.      -7 • 3

  ——————————————————  =   ——————

        L.C.M               12  

Adding fractions that have a common denominator :

3.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

-1 • 4 + -7 • 3     -25

———————————————  =  ———

      12            12

Final result :

 -25            

 ——— = -2.08333

 12            

Processing ends successfully

plz mark me as brainliest :)

7 0
3 years ago
Read 2 more answers
there are 13 animals in the barn. some are chickens and some are goats. there are 48 legs in all. how many of each animal are th
romanna [79]

Answer:

Step-by-step explanation:

chickens + goats = 13

so...

c + g = 13, so...

g = (13 - c)

2 legs times the number of chickens (2c) + 4 legs times the number of goats (4g) = 48 total legs. So...

2c + 4(13-c) = 48, so

2c + 52 - 4c = 48, so

-2c = -4, so

2c = 4, so

c = 2.

There are 2 chickens, and therefore 11 goats.

5 0
3 years ago
Can someone double check me???
kvv77 [185]
You’re correct I think
8 0
3 years ago
Simplify the following expression: -7(3e-2f+4)+6e-2
tankabanditka [31]

Answer:

-15e+14f-30

Step-by-step explanation:

First using distributive property to expand the first term:

-21e+14f-28+6e-2

Combining like terms:

-15e+14f-30

3 0
3 years ago
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