A physics department has a Foucault pendulum, a long-period pendulum suspended from the ceiling. The pendulum has an electric ci
rcuit that keeps it oscillating with a constant amplitude. When the circuit is turned off, the oscillation amplitude decreases by 50% in 37 minutes. a. What is the pendulum's time constant?
b. How much additional time elapses before the amplitude decreases to 25% of its initial value?
T=-2220/ln(.5) = 3202.78sec / 60 secs = 53.38 mins -> first part of the answer.
The second part is really easy. It took 37 mins to decay half way. meaning to decay another half of 50% which equals 25% it will take an additional 37 mins!
No because like my other answer if we put to many diesels on it it will crack and little by little it will break eventually everyone will come tumbling into the water making them drown because they can't get the buckles loose or they wanted to save their families lives
