Answer:I think the answer is letter B.
Step-by-step explanation:
The number of shelves stephen can make is approximately 27
<h3><u>Solution:</u></h3>
Given that Stephen makes wooden shelves for his room
Stephen wants to make the shelves 3/4 foot long
He starts with a board that is 20 feet long
To find: number of shelves he can make
So the number of shelves stephen can make can make is found out by dividing 20 feet long board by 3/4 foot long


So the number of shelves stephen can make is approximately 27
Answer:
The bottle of orange juice will have higher amounts of vitamin C per serving, as it will have 125 mg against 90 mg of the cranberry juice.
Step-by-step explanation:
To determine the amount of vitamin C in each serving of fruit juice, knowing that the bottle of orange juice contains 750 mg of vitamin C and 6 servings, while the bottle of cranberry juice contains 135 mg and 1.5 servings, you must perform the following calculation:
Orange: 750/6
Orange: 125 mg per serving
Cranberry: 135 / 1.5
Cranberry: 90 mg per serving
Thus, the bottle of orange juice will have higher amounts of vitamin C per serving, as it will have 125 mg against 90 mg of the cranberry juice.
Answer:
a) 0.9
b) Mean = 1.58
Standard Deviation = 0.89
Step-by-step explanation:
We are given the following in the question:
A marketing firm is considering making up to three new hires.
Let X be the variable describing the number of hiring in the company.
Thus, x can take values 0,1 ,2 and 3.

a) P(firm will make at least one hire)

Also,


b) expected value and the standard deviation of the number of hires.
![E(x^2) = \displaystyle\sum x_i^2P(x_i)\\=0(0.1) + 1(0.4) + 4(0.32) +9(0.18) = 3.3\\V(x) = E(x^2)-[E(x)]^2 = 3.3-(1.58)^2 = 0.80\\\text{Standard Deviation} = \sqrt{V(x)} = \sqrt{0.8036} = 0.89](https://tex.z-dn.net/?f=E%28x%5E2%29%20%3D%20%5Cdisplaystyle%5Csum%20x_i%5E2P%28x_i%29%5C%5C%3D0%280.1%29%20%2B%201%280.4%29%20%2B%204%280.32%29%20%2B9%280.18%29%20%3D%203.3%5C%5CV%28x%29%20%3D%20E%28x%5E2%29-%5BE%28x%29%5D%5E2%20%3D%203.3-%281.58%29%5E2%20%3D%200.80%5C%5C%5Ctext%7BStandard%20Deviation%7D%20%3D%20%5Csqrt%7BV%28x%29%7D%20%3D%20%5Csqrt%7B0.8036%7D%20%3D%200.89)