Question

Use the discriminant to determine how many solutions are possible for the following equation?(show work)

Answer 1

Answer:

see the explanation

Step-by-step explanation:

The correct question is

Use the discriminant to determine how many solutions are possible for the following equation (show  work).

5x^2-3x+4=0

we know that

The discriminant for a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$D=b^2-4ac$

If D=0 then the equation has only one real solution

If D>0 then the equation has two real solutions

If D<0 then the equation has no real solutions (two complex solutions)

in this problem we have

$5x^{2} -3x+4=0$  

so

$a=5\\b=-3\\c=4$

substitute

$D=-3^2-4(5)(4)$

$D=-71$

so

The equation has no real solutions, The equation has two complex solutions

therefore

I know there are___No____

real solutions to the equation in problem 4 because  ___the discriminant is negative___