To solve this, you’ll first need to solve for their slopes.
The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3
We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3
The equation you get it y = 1/3x + b.
Now you will need to solve for b by substituting in the first ordered pair of line R.
2 = 1/3(1) + b.
Once you solve for b, you should get 5/3 and y = 1/3x + 5/3
Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.
y = 1/3(10) + 5/3.
Your solution should be 5.
So your answer is: a = 5
Answer:
The best way of writing this answer in an inequality pattern is 50 ≤ x ≥ 70
Step-by-step explanation:
The variable "x" is said to be greater than or equal to 50, that means that x could be 50, 51, 52, 53, 54......to infinity, all these values are true for x.
The second solution said x is greater or equal to 70. This also means that x could be 70, 71, 72, 73, ......... to infinity.
The inference that can be drawn from here is that x actually started from 50, so anything lesser than 50 is lesser than x, so 50 ≤ x. We can join the two answers together to get a range in a form like: 50 ≤ x ≥ 70
Answer:
B. 550 - 2x > 850 - 6x
Step-by-step explanation:
Answer:
x=-42 to check ur answer place it like this 7-(-42) =49 which is correct
When you arrange the N points in sequence around the polygon (clockwise or counterclockwise), the area is half the magnitude of the sum of the determinants of the points taken pairwise. The N determinants will also include the one involving the last point and the first one.
For example, consider the vertices of a triangle: (1,1), (2,3), (3,-1). Its area can be computed as
(1/2)*|(1*3-1*2) +(2*-1-3*3) +(3*1-(-1)*1)|
= (1/2)*|1 -11 +4| = 3
