Question

What is the sum of an infinite geometric series if the first term is 156 and the common ratio is 2⁄3?

Answer 1

Answer:

B. 468

Step-by-step explanation:

We have

$a_1=156,\ r=\dfrac{2}{3}$

If |r| < 1, then the formula of a sum of an infinite geometric sequence is:

$S=\dfrac{a_1}{1-r}$

Substitute:

$S=\dfrac{156}{1-\frac{2}{3}}=\dfrac{156}{\frac{1}{3}}=156\cdot\dfrac{3}{1}=468$