Chang knows one
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Answer:
And we can find this probability with this difference and using the normal standard table:
Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women
Step-by-step explanation:
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where and
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability with this difference and using the normal standard table:
Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women