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Alina [70]
3 years ago
8

To complete the square, how do you find the value that must be added to the expression to make a perfect square trinomial? What

is the value?
x^2 + 2/5x + ?
A) square 2/5 and add to both sides; 4/25
B) take half of 2/5 and add to both sides; 1/5
C) square half of 2/5 and add to both sides; 1/25
D) take half of 2/5 and add the opposite to both sides; −1/5
Mathematics
2 answers:
Molodets [167]3 years ago
3 0
Take half of the coefficient of x (which is 2/5) and square it:

[ (1/2)(2/5) ]^2 = (1/5)^2 = 1/25, or 0.04

Thus, to rewrite x^2 + (2/5)x to include a perfect square trinomial,

x^2 + (2/5)x  = x^2 + (2/5)x + (1/5)^2 - (1/5)^2, or

                 (x+1/5)^2 - (1/5)^2, or (x + 1/5)^2 - 1/25
Readme [11.4K]3 years ago
3 0

Answer:The answer is C

Step-by-step explanation:

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emmainna [20.7K]

Answer:

x < -3/2

Step-by-step explanation:

8 0
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What's the solution to the inequality????? 20 points
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the answer is A

Step-by-step explanation:

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2 years ago
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Maya has 3 times as many dimes as nickels. She has 4 more quarters than nickels. if she has a total of $9.40, how many of each t
puteri [66]

Answer:  nickels = 14, dimes = 42, quarters = 18

<u>Step-by-step explanation:</u>

Let n represent nickels <em>which has a value of $0.05 </em>

Let d represent dimes <em>which has a value of $0.10</em>

Let q represent quarters <em>which has a value of $0.25</em>

It is given that:

                       n = n

                      d = 3n

                      q = n + 4

and their total value is $9.40    ⇒     n + d + q = $9.40

Use substitution to find the quantity of nickels:

.05(n) + .10(3n) + .25(n + 4) = 9.40

 5n    +  10(3n) +   25(n+4)   = 940           <em>multiplied by 100 </em>

 5n    +   30n   +  25n + 100 = 940          <em>distributed</em>

                            60n + 100 = 940          <em>added like terms</em>

                            60n           = 840          <em>subtracted 100</em>

                                 n           = 14            <em>divided by 60</em>

n = 14

                d = 3n

                   = 3(14)

                   = 42

                                       q = n + 4

                                          = (14) + 4

                                           = 18

4 0
3 years ago
An airplane flies due north from ikeja airport for 500km.It then flies on a bearing of 060 from a further distance of 300km befo
Nata [24]

Answer:

482 km

63.94 degrees

Step-by-step explanation:

to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.

Cosine rule states that

C = \sqrt{A^{2} + B^{2} -2AB   cos(c)  }

where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060

solving now, we have

C = \sqrt{500^{2} + 300^{2} -2 * 500 * 300 cos(60)  }

C = \sqrt{250000 + 90000 - [215000   cos(60)  }]

C = \sqrt{340000 - [215000 * 0.5  }]

C = \sqrt{340000 - [107500  }]

C =\sqrt{232500}

C = 482 km

The bearing can be gotten by using the Sine Rule.

\frac{sina}{A} = \frac{sinc}{C}

sina/500 = sin60/482

482 sina = 500 sin60

sina = \frac{500 sin60}{482}

sina = 0.8983

a = sin^-1(0.8983)

a = 63.94 degrees

6 0
3 years ago
On Monday Headley paid $1.70 for two of coffee and one doughnut, including the tip. On Tuesday he paid $1.65 for two doughnuts a
stich3 [128]

Answer:

i dont wanna say

Step-by-step explanation:

3 0
3 years ago
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