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Rudiy27
3 years ago
14

Adam’s house is 2 centimeters from Juan’s house on a map. If each centimeter on the map represents 6 kilometers, how far apart a

re the two houses?
Mathematics
2 answers:
nataly862011 [7]3 years ago
5 0
12 kilometres. 

If one centimetre is equivalent to 6 kilometres then two centimetres is equivalent to 12.<span />
crimeas [40]3 years ago
3 0
If one centimeter on the map represents 6 kilometers, then all you need to do to find out how far Adam's house is from Juan's is to multiply the distance between the two houses on the map in centimeters by the amount of kilometers that each centimeter on the map represents.

2 * 6 = 12

Which is our answer.
Adam's house is 12 kilometers from Juan's house.
Hope that helped! =)
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Can someone tell me what’s going on here
lora16 [44]

Answer:

c = 105 degres

Step-by-step explanation:

When two lines cross like that and form an x, the opposite sides are equal (so the angle below the 75 degree one is also 75 degees). Using this, you can figure out the rest.

If both the top an bottom are equal, you know that 150 degres are taken (75+75) and you know that there can only be 360 degres in total here, so you subtract 150 from 360 and get 210. Now you know that the last two sides together are 210, and since they are equal, you divide it by two to get 105 degrees.

8 0
3 years ago
The calibration of a scale is to be checked by weighing a 13 kg test specimen 25 times. Suppose that the results of different we
Natali5045456 [20]

Solution :

a).

Given : Number of times, n = 25

            Sigma, σ = 0.200 kg

            Weight, μ = 13 kg

Therefore the hypothesis should be tested are :

$H_0 : \mu = 13 $

$H_a : \mu \neq 13$

b). When the value of $\overline x = 12.84$

 Test statics :

   $Z=\frac{(\overline x - \mu)}{\frac{\sigma}{\sqrt n}} $

  $Z=\frac{(14.82-13)}{\frac{0.2}{\sqrt {25}}} $

          $=\frac{1.82}{0.04}$

          = 45.5  

P-value = 2 x P(Z > 45.5)

            = 2 x 1 -P (Z < 45.5) = 0

Reject the null hypothesis if P value  < α = 0.01 level of significance.

So reject the null hypothesis.

Therefore, we conclude that the true mean measured weight differs from 13 kg.

3 0
3 years ago
A calculator is broken so that the only keys that still work are the $\sin$, $\cos$, $\tan$, $\cot$, $\arcsin$, $\arccos$, and $
miskamm [114]
What is this check the q again
7 0
2 years ago
Given the piecewise function shown below, select all the statements that are true.
Lena [83]
C
because it is the only logical answer
4 0
3 years ago
A seagull was flying about sea level looking to catch a fish below sea level. The elevation above sea level was 125 1/2 feet. He
frez [133]

Answer:

The seagull's position halfway is 85.5 feet.

Step-by-step explanation:

The seagull is at 125 1/2 feet above the sea level.

The fish is at 45 1/2 feet below the sea level.

The distance between the seagull and fish = seagull's distance above the sea level + fish's distance below the sea level

                                                  = 125 1/2 + 45 1/2

                                                  = \frac{251}{2} + \frac{91}{2}

                                                  = \frac{342}{2}

                                                  = 171

The distance between the seagull and fish is 171 feet.

Since the seagull stops halfway, then;

seagull's position = \frac{171}{2}

                             = 85.5

The seagull's position halfway is 85.5 feet.

8 0
2 years ago
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