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3 years ago

5

Does -|-4|=|-(4)| justify your answer

1 answer:

a_sh-v [17]3 years ago

8 0

- |-4| = -4....absolute values are positive, but if the negative sign lies outside of the absolute value bars, it is not effected.

| - (4) | = | -4 | = 4...this one becomes positive because the negative sign lies inside of the absolute value bars.

So, no, they are not equal.

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Under the last-in, first-out (LIFO) inventory valuation method, a price index for inventory must be established for tax purposes

frosja888 [35]

Answer:

The laspeyres method of weighted aggregate price index is used of LIFO inventory valuation, therefore laspeyres index number is 106.08

Step-by-step explanation:

First of all we would have to perform the following table:

Product Ending Inventory(Q0) Begining(P0) Ending(P1) P0×Q0 P1×Q0

A 500 0.15 0.21 75 105

B 50 1.60 1.80 80 90

C 100 4.50 4.20 450 420

D 40 12.00 13.40 480 536

Total 1085 1151

Therefore, using laspeyres index number, we calculate the following:

laspeyres index number=(∑P1×Q0/∑P0×Q0)×100

laspeyres index number=(1151/1085)×100

laspeyres index number=106.08

8 0

4 years ago

Find the value of x. A. 53–√ in B. 241−−√ in C. 55–√ in D. 9

castortr0y [4]

Answer:

<h2>x = 5√3 inches</h2>

Step-by-step explanation:

Since the triangle is a right angled triangle we can use Pythagoras theorem to find the missing side x

Using Pythagoras theorem we have

${a}^{2} = {b}^{2} + {c}^{2}$

where a is the hypotenuse

Substitute the values into the above formula

The hypotenuse is 10 inches

We have

${10}^{2} = {5}^{2} + {x}^{2}$

${x}^{2} = {10}^{2} - {5}^{2}$

${x}^{2} = 100 - 25$

${x}^{2} = 75$

We have the final answer as

<h3>x = 5√3 inches</h3>

Hope this helps you

3 0

3 years ago

Which of the following equations is equivalent to the equation 6x-y=1

kondaur [170]

A. 6x-y=1 can go to 6x-y-1=0 and then 6x-1 = y

3 0

4 years ago

Read 2 more answers

Please answer asap...

ehidna [41]

Answer:

The answer is C pay attention in class next time

6 0

3 years ago

The given two-parameter family is a solution of the indicated differential equation on the interval

mr_godi [17]

Answer:

I do 1 option for you as an example, you need to check the leftover by yourself.

Step-by-step explanation:

for d) y(0) = 0 and y'(pi) =0

$y(0) = C_1e^0cos(0)+ C_2 e^0 sin(0) = 0 \longrightarrow C_1 = 0$

$y(x) ' = C_1e^x cos(x) - C_1e^x sin (x) + C_2e^x sin(x) + C_2e^x cos(x)$

$y(\pi)'=C_1e^\pi cos(\pi)- C_1e^\pi sin(\pi)+ C_2e^\pi sin(\pi) + C_2e^\pi cos (\pi)$

Replace $C_1 = 0$ we have

$y'(\pi) = -C_2e^\pi = 0$

if and only if $C_2 =0$

Hence the given solution does not work.

then, d is NOT the correct answer.

3 0

3 years ago