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iris [78.8K]
3 years ago
7

98 - 5q for q = 7 help

Mathematics
2 answers:
ruslelena [56]3 years ago
6 0
63.

98-5q
plug 7 in and take out q
98- 5×7
follow pemdas. multiplication and division go before adding and subtracting, m and d are before a and s in pemdas.


5×7= 35

98-35=
63
Molodets [167]3 years ago
3 0

you have to multiply the 5 and the 7 and you get 35 then subtract 98 and 35 and you get 63

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Two number cubes are tossed. What is P(4, 6)?<br><br> O.1/6<br> O.1/12<br> O.1/3<br> O.1/36
Bezzdna [24]

The value of P(4, 6) when the two number cubes are tossed is 1/36

<h3>How to determine the probability?</h3>

On each number cube, we have:

Sample space = {1, 2, 3, 4, 5, 6}

The individual probabilities are then represented as:

P(4) =1/6

P(6) =1/6

The value of P(4, 6) when the two number cubes are tossed is:

P(4, 6) = P(4) * P(6)

This gives

P(4, 6) = 1/6 * 1/6

Evaluate

P(4, 6) = 1/36

Hence, the value of P(4, 6) when the two number cubes are tossed is 1/36

Read more about probability at:

brainly.com/question/24756209

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6 0
1 year ago
!!!!HELP NEEDED!!!!
Svetllana [295]

It is true that the product of two consecutive even integers are always one less than the square of their average.

<u>Step-by-step explanation</u>:

Let the two consecutive odd integers be 1 and 3.

  • The product of 1 and 3 is (1\times3)=3
  • The average of 1 and 3 is (1+3)/2 =4/2 = 2
  • The square of their average is (2)² = 4

∴ The product 3 is one less than the square of their average 4.

Let the two consecutive even integers be 2 and 4.

  • The product of 2 and 4 is (2\times4)=8
  • The average of 2 and 4 is (2+4)/2 =6/2 = 3
  • The square of their average is (3)² = 9

∴ The product 8 is one less than the square of their average 9.

Thus, It is true that the product of two consecutive even integers are always one less than the square of their average.

4 0
3 years ago
15. Scott and Tara were asked to find the
Dmitriy789 [7]

Answer:

Both Scott and Tara have responded correctly.

Step-by-step explanation:

we know that

The area of a trapezoid is equal to

A=(1/2)[b1+b2]h

we have

b1=16 cm

b2=24 cm

h=8 cm -----> <em>Note</em> The height is 8 cm instead of 18 cm

substitute

A=(1/2)[16+24](8)

A=160 cm²

<em>Verify Scott 's work</em>

<em>Note</em> Scott wrote A = (1/2)(24 + 16)(8) instead of A = 2(24 + 16)(8)

Remember that the Commutative Property establishes "The order of the addends does not alter its result"

so

(24+16)=(16+24)

A = (1/2)(24 + 16)(8)=160 cm²

<em>Verify Tara's work</em>

<em>Note</em> Tara wrote A = (1/2)(16+24)(8) instead of A = (16 + 24)(8)

A = (1/2)(16+24)(8)=160 cm²

5 0
3 years ago
In the parabola y = (x + 12 + 2, what is the vertex?
VladimirAG [237]

Answer:

The vertex is the point (-6,-34)

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

y=a(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

In this problem we have

y=x^{2}+12x+2

Convert in vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

y-2=x^{2}+12x

Complete the square . Remember to balance the equation by adding the same constants to each side.

y-2+36=x^{2}+12x+36

y+34=x^{2}+12x+36

Rewrite as perfect squares

y+34=(x+6)^{2}

y=(x+6)^{2}-34

The vertex is the point (-6,-34)

4 0
3 years ago
How much area is left over
LenaWriter [7]
I won't tell you the answer but I'll tell you how to do it

first, find the area of the rectangle (lxw)

Next, find area of the triangle (BxHx.5)

Then, subtract the area of the rectangle to the area of the triangle
5 0
3 years ago
Read 2 more answers
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