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3 years ago

Finding domaind and range of polynomial functions.What is the domain?

Mathematics

1 answer:

Lapatulllka [165]3 years ago

7 0

Answer:

Step-by-step explanation:

dentification string that defines a realm of administrative autonomy, authority or control within the Internet.

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What types of driving behaviors help make a driver safer? Press Space to open If there is a group of 100 drivers and 50 take a s

olasank [31]

It should be noted that the driving behaviors that can make a driver safe include:

Complying with road rules.
Excellent sense of navigation.
Being patient and courteous towards others.
Be responsible and reliable.

<h3>Driving behaviors.</h3>

It should be noted that driver behavior simply means the characteristics band actions that a driver performs when driving.

In order to prevent accidents, it's important for drivers to comply with road rules, have an excellent sense of navigation, and be patient and courteous towards others.

Learn more about driving on:

brainly.com/question/1071840

8 0

3 years ago

Tolong bantu jawab yaa PAKAI CARAA

yanalaym [24]

B? 

1 2/3 ÷ 1 1/9 = 1.5

2.34 ÷ 0.6 = 3.9

7 0

4 years ago

The angle \theta_1θ

enyata [817]

Answer:

$sin\theta_1 = \dfrac{\sqrt{217}}{19}$

Step-by-step explanation:

It is given that:

$cos\theta_1 = -\dfrac{12}{19}$

And we have to find the value of $sin\theta_1 = ?$

As per trigonometric identities, the relation between $sin\theta\ and \ cos\theta$ can represented as:

$sin^2\theta + cos^2\theta = 1$

Putting $\theta_1$ in place of $\theta$ Because we are given

$sin^2\theta_1 + cos^2\theta_1 = 1$

Putting value of cosine:

$cos\theta_1 = -\dfrac{12}{19}$

$sin^2\theta_1 + (\dfrac{12}{19})^2 = 1\\\Rightarrow sin^2\theta_1 + \dfrac{144}{361} = 1\\\Rightarrow sin^2\theta_1 = 1-\dfrac{144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{217}{361}\\\Rightarrow sin\theta_1 = +\sqrt{\dfrac{217}{361}}, -\sqrt{\dfrac{217}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{\sqrt{217}}{19}, -\dfrac{\sqrt{217}}{19}$

It is given that $\theta_1$ is in 2nd quadrant and value of sine is always positive in 2nd quadrant. So, the answer is.

$\Rightarrow sin\theta_1 = \dfrac{\sqrt{217}}{19}$

8 0

3 years ago

find the equation in slope intercept form of a line that is a perpendicular bisector of segment AB with endpoints A(-5,5) and B(

aliina [53]

The equation in slope intercept form of a line that is a perpendicular bisector of segment AB with endpoints A(-5,5) and B(3,-3) is y = x + 2

<h3>Solution:</h3>

Given, two points are A(-5, 5) and B(3, -3)

We have to find the perpendicular bisector of segment AB.

Now, we know that perpendicular bisector passes through the midpoint of segment.

The formula for midpoint is:

$\text { midpoint }=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$Here x_1 = -5 ; y_1 = 5 ; x_2 = 3 ; y_2 = -3$

$\text { So, midpoint of } A B=\left(\frac{-5+3}{2}, \frac{5+(-3)}{2}\right)=\left(\frac{-2}{2}, \frac{2}{2}\right)=(-1,1)$

Finding slope of AB:

$\text { Slope of } A B=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\text { Slope } m=\frac{-3-5}{3-(-5)}=\frac{-8}{8}=-1$

We know that product of slopes of perpendicular lines = -1

So, slope of AB $\times$ slope of perpendicular bisector = -1

- 1 $\times$ slope of perpendicular bisector = -1

Slope of perpendicular bisector = 1

We know its slope is 1 and it goes through the midpoint (-1, 1)

The slope intercept form is given as:

y = mx + c

where "m" is the slope of the line and "c" is the y-intercept

Plug in "m" = 1

y = x + c ---- eqn 1

We can use the coordinates of the midpoint (-1, 1) in this equation to solve for "c" in eqn 1

1 = -1 + c

c = 2

Now substitute c = 2 in eqn 1

y = x + 2

Thus y = x + 2 is the required equation in slope intercept form

7 0

4 years ago

Solve using traditional division: 8,184 62

EleoNora [17]

Answer:

131

Step-by-step explanation:

You just put the biggest number in the box, and then you divide by the lower number.

4 0

3 years ago