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umka2103 [35]
3 years ago
8

What is the length of dk? 7.0 3.5 8.5 12.7

Mathematics
1 answer:
Anarel [89]3 years ago
4 0
To get the value of DK we use proportionality:
AK/EK=BK/KD
thus plugging the values we get:
14/17=7/KD
getting the reciprocal of getting both sides we have:

17/14=KD/7
thus
KD=17/14×7
KD=8.5
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Jim is hiking 4 1/2 mile trail.He has already hiked 2 5/8 miles.How much further does he have to hike?
musickatia [10]

Answer:

1 7/8

Step-by-step explanation:

2 5/8

+1 7/8= 4 1/2

  1. 7=3+4
  2. 5+3=8
  3. 2 5/8 + 3/8= 3
  4. 3 + 1= 4
  5. 4 + 4/8= 4 4/8
  6. 4 4/8 = 4 1/2

3 0
3 years ago
  Express 35.4% as a decimal.
lakkis [162]
It is because the 35.4% divided the 100% total is B. 0.354
8 0
4 years ago
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The 5th grade classes at Brookfield School used 5 identical buses to go on a field trip.
erik [133]

1/8 x 5 = 5/8

5/8 of the passengers were adults :)

7 0
3 years ago
Please answer this worth 10 points<br><br> look in the image plz
Pachacha [2.7K]
1) It’s true because -5 is way smaller than 3. All the negatives are below the 0 and everything below the 0 is lower than everything above the 0.

2) false. it’s false because in order -5 isn’t even close to 3

3) false.. It’s false because when you have those 2 line that are covering the -5 that means it’s “transforming” into a positive number. So therefore it’s would be 5>3 that would make it true.

4) True. it’s true because like I said the to lines mean the absolute value of something. So it’s being switch to a positive number


Hope this helps :)
5 0
3 years ago
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three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal
Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

=     x + x + (x + \frac{6}{5}) = \frac{27}{4}

=     3x + \frac{6}{5} = \frac{27}{4}

=     3x = \frac{27}{4} - \frac{6}{5}

( let's take the LCM of 4 and 5 = 20

=     3x = \frac{135}{20} - \frac{24}{20}

=     3x = \frac{111}{20}

=       x = \frac{111}{20} ÷ \frac{3}{1} = \frac{111}{20} × \frac{1}{3} = \frac{37}{20}

So, the weight of the equal bags are \frac{37}{20} and the weight of the third bag ( heavy one ) is \frac{37}{20} + \frac{6}{5} = \frac{37}{20} + \frac{24}{20} = \frac{61}{20}

1st bag =     \frac{37}{20} kg

2nd bag =  \frac{37}{20} kg

3rd bag =   \frac{61}{20} kg

Hope it helps...

7 0
3 years ago
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