In triangle ABC, it is given that angle A is 59 degrees and angle B is 53 degrees. The altitude from B to line AC is extended un
til it intersects the line through A that is parallel to segment BC; they meet at K. Calculate the size of angle AKB.
2 answers:
Answer:
∠AKB = 22°
Step-by-step explanation:
Call the point of intersection of BK and AC point P. Then line BK is a transversal to parallel lines AK and BC. Alternate interior angles AKB and PBC will be congruent.
We know that angle PCB is 68°, the difference between 180° and the sum of the two given angles in ΔABC:
∠PCB = 180° -∠PAB -∠ABC = 180° -59° -53° = 68°
Since PB is an altitude, ∠CPB is a right angle. Then ∠PBC is the complement of ∠PCB, so is ...
∠PBC = 90° -68° = 22°
As we said, this is congruent to ∠AKB, so ...
∠AKB = 22°
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