A metallurgist has one alloy containing 32% copper and another containing 65% copper. How many pounds of each alloy must he use
1 answer:
Answer:
<h2>30.67 pounds of 32% copper alloy and 10.33 pounds of 65% copper alloy</h2>Step-by-step explanation:
First alloy contains 32% copper and the second alloy contains 65% alloy.
We wish to make 44 pounds of a third alloy containing 42% copper.
Let the weight of first alloy used be in pounds and the weight of second alloy used be
in pounds.
Total weight =
Total weight of copper =
Subtracting 32 times first equation from second equation,
∴ 30.67 pounds of first alloy and 13.33 pounds of second alloy were used.
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Answer:
78 ml of 7% vinegar and 312 ml of 12% vinegar.
Step-by-step explanation:
Let x represent ml of 7% vinegar brand and y represent ml of 12% vinegar brand.
We have been given that chef wants to make 390 milliliters of the dressing. We can represent this information in an equation as:
We are also told that 1st brand 7% vinegar, so amount of vinegar in x ml would be .
The second brand contains 12 vinegar, so amount of vinegar in y ml would be .
We are also told that the chef wants to make 390 milliliters of a dressing that is 11% vinegar. We can represent this information in an equation as:
Upon substituting equation (1) in equation (2), we will get:
Therefore, the chef should use 78 ml of the brand that contains 7% vinegar.
Upon substituting in equation (1), we will get:
Therefore, the chef should use 312 ml of the brand that contains 12% vinegar.