Ask question

Ask question

All categories

BaLLatris [955]

3 years ago

15

If you work for an hourly wage, your gross pay is a function of the number of hours that you work. Your hourly wage is $8 per ho

ur. Assuming you work 40 hours per week, what is the practical domain and the practical range of the function?

1 answer:

elixir [45]3 years ago

7 0

I belive your answer is 320
Happy to assist you!

You might be interested in

How do you figure out how many days they will once again be at opposition with one another?

MissTica

You will need to find a common multiple of the two. For example:

2: 2, 4, 6
3: 3, 6

The common multple here is 6, so the answer is 6.

Thanks,
Whiiz

3 0

3 years ago

(-6x) / (-2)<br> Simplify.<br><br> 12x<br> 4x<br> 3x<br> 1/12x

ElenaW [278]

$\dfrac{-6x}{-2}=\dfrac{-6}{-2}x=3x$

8 0

2 years ago

HELPPPP. Need help asap.

mamaluj [8]

Answer:

Just learned this-

They are both 1 because of it being to the power of zero and if you type the both in like...

Step-by-step explanation:

sin(73)^0 you get 1

tan(12)^0 you get 1

6 0

2 years ago

Anyone can help me solve this equation using cross multiplying

Natali5045456 [20]

9514 1404 393

Answer:

x = 1 or 5

Step-by-step explanation:

The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...

$\displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\ \longrightarrow\ (x-1)(3x-1)=(7)(2x-2)$

Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.

$3x^2-4x+1=14x-14\\\\3x^2-18x+15=0\qquad\text{subtract $14x-14$}\\\\x^2-6x+5=0 \qquad\text{divide by 3}\\\\(x-1)(x-5)=0\qquad\text{factor}\\\\x\in\{1,5\}$

_____

<em>Comment on "cross multiply"</em>

Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes <em>what the result looks like</em>. It doesn't adequately describe how you get there. The <em>one and only rule</em> in solving Algebra problems is "<em>whatever is done to one side of the equation must also be done to the other side of the equation</em>." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.

What looks like "cross multiply" is really "<em>multiply by the product of the denominators</em> and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.

$\displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\\\\\frac{x-1}{7}\times7(3x-1)=\frac{2x-2}{3x-1}\times7(3x-1)\\\\(x-1)(3x-1)=(2x-2)(7)\qquad\textit{looks like}\text{ cross multiply}$

8 0

2 years ago

How would I do this question.

olga2289 [7]

Answer:

The density of cube is 6.17959 $\frac{g}{cm^{3} }$

Step-by-step explanation:

The density is given by ration of a mass of body and volume occupied by a body.

$\rho = \frac{m}{V}$

Where,

$\rho$ is density.

m is mass of a body

V is the volume of a body

Given that one side of the cube is 0.53cm

Hence, the volume of a body is V= $0.53^{3}$ =0.148877 $cm^{3}$

Now, the Density of the cube will be

$\rho = \frac{m}{V}$

$\rho = \frac{0.92}{0.148877}$

$\rho =6.17959$

Thus, The density of cube is 6.17959 $\frac{g}{cm^{3} }$

3 0

3 years ago