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3 years ago

Nitric oxide is unique because it:

Chemistry

1 answer:

musickatia [10]3 years ago

8 0

I believe ur answer is b. Is not stored in vesicles but is made on demand.
hope this helps.

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The Ksp for CaCO3 is 3.8 x 10-9. Determine the concentration in moles/liter of calcium ion in a saturated solution of calcium ca

balu736 [363]

Answer: c. $6.2\times 10^{-5}moles/L$

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as $K_{sp}$

The equation for the ionization of the calcium carbonate is given as:

$CaCO_3\leftrightharpoons Ca^{2+}+CO_3^{2-}$

We are given:

$K_{sp}=3.8\times 10^{-9}$

By stoichiometry of the reaction:

1 mole of $CaCO_3$ gives 1 mole of $Ca^{2+}$ and 1 mole of $CO_3^{2-}$ .

Expression for the equilibrium constant of $CaCO_3$ will be:

$K_{sp}=[Ca^{2+}][CO_3^{2-}]$

$3.8\times 10^{-9}=[s][s]$

$3.8\times 10^{-9}=s^2$

$s=6.2\times 10^{-5}moles/L$

Hence, the concentration in moles/liter of calcium ion in a saturated solution of calcium carbonate is $6.2\times 10^{-5}moles/L$

8 0

4 years ago

Why is it important that a hypothesis be stated so that it can be modified?

ANEK [815]

Because you need to know what you are looking for before actually trying something so you can prevent any accidents by doing stuff at random

3 0

3 years ago

Which one of the following items does NOT characterize a reducing agent? a. A reducing agent loses electrons. b. A reducing agen

Ad libitum [116K]

Answer: D

Explanation:

A reducing agent is a species that reduces other compounds, and is thereby oxidized. The whole compound becomes the reducing agent. In other words, of a compound is oxidized, then they are the reducing agent. On the other hand, if the compound is reduced, it is an ozidizing agent.

Since we have established that a reducing agent is the compound being oxidized, we know that A is not our answer. An oxidized compound is losing electrons. Choice A states exactly this.

For B, this is true as we have established this already.

C is also correct. Since a reducing agent loses electrons, it becomes more positive. This makes the oxidation number increase.

D would be our correct answer. It is actually a good oxidizing agent is a metal in a high oxidation state, such as Mn⁷⁺.

4 0

3 years ago

The equation represents the decomposition of a generic diatomic element in its standard state. 12X2(g)⟶X(g) Assume that the stan

aliina [53]

Answer:

$K^{2000K}=0.774\\\\K^{3000K}=12.56$

Explanation:

Hello,

In this case, considering the reaction, we can compute the Gibbs free energy of reaction at each temperature, taking into account that the Gibbs free energy for the diatomic element is 0 kJ/mol:

$\Delta _rG=\Delta _fG_{X}-\frac{1}{2} \Delta _fG_{X_2}=\Delta _fG_{X}$

Thus, at 2000 K:

$\Delta _rG=\Delta _fG_{X}^{2000K}=4.25kJ/mol$

And at 3000 K:

$\Delta _rG=\Delta _fG_{X}^{3000K}=-63.12kJ/mol$

Next, since the relationship between the equilibrium constant and the Gibbs free energy of reaction is:

$K=exp(-\frac{\Delta _rG}{RT} )$

Thus, at each temperature we obtain:

$K^{2000K}=exp(-\frac{4250J/mol}{8.314\frac{J}{mol\times K}*2000K} )=0.774\\\\K^{3000K}=exp(-\frac{-63120J/mol}{8.314\frac{J}{mol\times K}*3000K} )=12.56$

In such a way, we can also conclude that at 2000 K reaction is unfavorable (K<1) and at 3000 K reaction is favorable (K>1).

Best regards.

4 0

3 years ago

What kind of solution would have a ka value that is much less than 1?

liberstina [14]

Answer:

D. A weakly acidic solution.

4 0

3 years ago