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liq [111]
3 years ago
10

How many representative particles are in a 53.79 gram sample of SrCO3?

Chemistry
2 answers:
Tcecarenko [31]3 years ago
8 0
Remember representative particles/ molecules/ atoms are all the same 

<span>convert from grams -> moles </span>

<span>hope this clears thing</span>
Irina18 [472]3 years ago
5 0
To find the number of particles, you need to use Avogadro's number

6.02 x 10^23= 1 mol

As you can see, before we can convert to particles, we need moles. So let's first convert grams to moles using the molar mass (molecular weight) of the compound

molar mass of SrCO₃= 87.6 + 12.0 + (3 x 16.0)= 147.6 g/mol

53.79 g (1 mol/ 147.6 g)= 0.364 mol

now let's convert moles to particles using Avogadro's number

0.364 mol SrCO₃ (6.02x10^23/ 1 mol)= 2.19 x 10^23


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the molecule structure of water contains two atoms of hydrogen and one of oxygen,water turns to vapor what happens to molecule s
sattari [20]

<em>Nothing happens</em>; water is still H₂O, even if it turns into ice, or vapor. Although, the molecules still move around faster, just like a normal gas would.

4 0
4 years ago
The density of gold is 19.3 g/cm³. What is the mass of 11.3 cm³ of gold?
telo118 [61]

Answer:

218.09g

Explanation:

the formula for density is mass/volume

you have volume so rlly what you have is 19.3g/cm3=m/11.3cm3

so mass equals density x volume

and 19.3 x 11.3 = 218.09

4 0
3 years ago
How does temperature affect the rate of a reaction?
BaLLatris [955]
B, more kinetic energy means more collisions and thus more reactions according to collision theory.
6 0
4 years ago
What is the wavelength of the line corresponding to n=4 in the balmer series? express your answer in nanometers to three signifi
liq [111]
Expression for the Balmer series to find the wavelength of the spectral line is as follows:
1 / λ = R (\frac{1}{2^{2} } -  \frac{1}{ n^{2}} )
Where, λ is wavelength, R is Rydberg constant, and n is integral value (4 here →  Fourth level) 
Substitute 1.097 x 10⁷ m⁻¹ for R and 4 for n in the above equation 
1 / λ = (1.097 x 10⁷ m⁻¹) (\frac{1}{2^{2} } -  \frac{1}{4^{2} }  ) 
   = 0.20568 x 10⁷ m⁻¹
λ = 4.86 x 10⁻⁷ m 
since 1 m = 10⁹ nm
λ = 486 nm 
8 0
3 years ago
6. At a glance, it appears like the law of
Mamont248 [21]

Energy and mass equivalence

Explanation:

The law of conservation of energy does not apply to nuclear reactions, the law of conservation of mass-energy makes more sense in this regard.

In nuclear reactions mass is transformed into energy. Therefore, it does not conform with the law of conservation of energy.

  • According to the law of conservation of energy "energy is neither created no destroyed but they are transformed from one form to another. "
  • In nuclear reactions, mass is usually lost. Mass is not conserved.
  • But, the mass is converted into energy and we say there is mass and energy equivalence for nuclear reactions.

Learn more:

Chemical laws brainly.com/question/5896850

#learnwithBrainly

4 0
3 years ago
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