<u>Answer:</u>
a. Oxidising agent: Cl₂
b. Reducing agent: NaBr
c. Oxidised: NaBr
d. Reduced: Cl₂
e. Oxidation numbers before reaction: Cl= 0, Na= +1, Br= -1
f. Oxidation numbers after reaction: Cl= -1, Na= +1, Br= 0
<u>Explanation:</u>
Oxidising agents reduces themselves, oxidising other elements/compounds.
Reducing agents oxidise themselves, reducing other elements/compounds.
Oxidation is the <u>loss</u> of electrons or an <u>increase</u> in oxidation number.
Reduction is the <u>gain</u> of electrons or <u>decrease</u> in oxidation number.
oxygen and silicon I believe
Answer: Heat dissipation mechanism
Explanation: Heat dissipation mechanism is a thermoregulatory response in humans whereby the hypothalamus of the brain initiates certain processes to reduce the high body temperature. Eg, sweating is initiated which helps cool down the body temperature, also superficial arteries are dilated, thereby leading to flushing and decreasing heatloss into the air. And metabolic heat production is also reduced.
Oxygen gains two electrons when it bonds to form a complete outer shell and magnesium loses two electrons when bonding to gain its full outer shell.
As electrons are negative, the oxygen (which gains electrons) will become negative and the magnesium (which loses electrons) will become positive.
The negative and positive ions will then attract to one another due to the magnetic pull of the positive and negative.
We have to know the molarity of solution obtained when 5.71 g of Na₂CO₃.10 H₂O is dissolved in water and made up to 250 cm³ solution.
The molarity of solution obtained when 5.71 g of sodium carbonate-10-water (Na₂CO₃.10 H₂O) is dissolved in water and made up to 250.0 cm^3 solutionis: (A) 0.08 mol dm⁻³
The molarit y of solution means the number of moles of solute present in one litre of solution. Here solute is Na₂CO₃.10 H₂O and solvent is water. Volume of solution is 250 cm³.
Molar mass of Na₂CO₃.10 H₂O is 286 grams which means mass of one mole of Na₂CO₃.10 H₂O is 286 grams.
5.71 grams of Na₂CO₃.10 H₂O is equal to 
= 0.0199 moles of Na₂CO₃.10 H₂O. So, 0.0199 moles of Na₂CO₃.10 H₂O present in 250 cm³ volume of solution.
Hence, number of moles of Na₂CO₃.10 H₂O present in one litre (equal to 1000 cm³) of solution is 
= 0.0796 moles. So, the molarity of the solution is 0.0796 mol/dm³ ≅ 0.08 mol/dm³
