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Klio2033 [76]
3 years ago
13

List five examples of matter and five examples that are not matter. Explain your answer.

Chemistry
1 answer:
ASHA 777 [7]3 years ago
3 0

Answer:

An apple,a person.a table,a computer,wood because they occupies space

non matter=Light, heat, kinetic and potential energy, and sound are non-matter because they are massless

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How long of time in hours will it take to plate out 1.0 kg Ni from aqueous Ni2+ solution, if the electrical current is 102 A? wh
netineya [11]

Answer: 8.95 hours

Explanation:

Ni^{2+}+2e^-\rightarrow Ni

96500\times 2=193000 Coloumb of electricity deposits 1 mole of Nickel

1 mole of Nickel weighs = 58.7 g

Given quantity = 1.0 kg = 1000 g  (1kg=1000g)

58.7 g of Nickel is deposited by 193000 C of electricity

1000 g of Nickel is deposited by =\frac{193000}{58.7}\times 1000=3287904.6C  of electricity

Q=I\times t

where Q= quantity of electricity in coloumbs  = 3287904.6C

I = current in amperes = 102 A

t= time in seconds = ?

3287904.6C=102A\times t

t=32234.359sec

t=8.95hr      (1h=3600 sec)

Thus 8.95 hours it takes to plate out 1.0 kg Ni from aqueous Ni^{2+} solution, if the electrical current is 102 A.

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3 years ago
What is the purpose of an experiment as a part of the scientific method
sladkih [1.3K]

Answer:

To test the hypothesis

Explanation:

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Can Petroleum be mixed with water?
Alik [6]

Answer:

No

Explanation:

Petroleum cant be mixed with water coz petroleum is less dense than water so petroleum will float on water.

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How many molecules of oxygen are produced when a sample of 38.9 g of water is decomposed by electricity?
statuscvo [17]

Answer:

A) 6.5\times 10^{23}\ \text{molecules}

Explanation:

m = Mass of water = 38.9

M = Molar mass of water = 18 g/mol

N_A = Avogadro's number = 6.022\times 10^{23}\ \text{mol}^{-1}

The reaction of electrolysis would be

2H_2O(l)\rightarrow 2H_2(g)+O_2(g)

Number of moles of H_2O

n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{38.9}{18}\ \text{mol}

From the reaction it can be seen that 2 moles of H_2O gives 1 mole of O_2

So, number of moles of O_2 produced is

\dfrac{38.9}{18}\times \dfrac{1}{2}=1.081\ \text{mol}

Number of molecules

1.081N_A=1.081\times 6.022\times 10^{23}\\ =6.5\times 10^{23}

So, 6.5\times 10^{23}\ \text{molecules} of oxygen is produced.

8 0
3 years ago
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