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Olin [163]
3 years ago
6

Which best describes the graphs of the line that passes through (−12, 15) and (4, −5), and the line that passes through (−8, −9)

and (16, 21)?
A)
They are parallel lines.


B)
They are vertical lines.


C)
They are perpendicular lines.


D)
They are intersecting lines.
Mathematics
2 answers:
drek231 [11]3 years ago
7 0

Answer:D) They are intersecting lines.

Step-by-step explanation: that other answer was wrong .

konstantin123 [22]3 years ago
4 0

Answer:

C) They are perpendicular lines.

Step-by-step explanation:

We first need to find the slope of the graph of the lines passing through these points using:

m =  \frac{y_2-y_1}{x_2-x_1}

The slope of the line that passes through (−12, 15) and (4, −5) is

m_{1} =  \frac{ - 5 - 15}{4 -  - 12}

m_{1} =  \frac{ - 20}{16}  =  -  \frac{5}{4}

The slope of the line going through (−8, −9) and (16, 21) is

m_{2} =  \frac{21 -  - 9}{16 -  - 8}

m_{2} =  \frac{21  + 9}{16  + 8}

m_{2} =  \frac{30}{24}  =  \frac{5}{4}

The product of the two slopes is

m_{1} \times m_{2} =  -  \frac{4}{5}  \times  \frac{5}{4}  =  - 1

Since

m_{1} \times m_{2} =  - 1

the two lines are perpendicular.

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Answer:

hope it helps you

Step-by-step explanation:

https://mathsolver.microsoft.com/en/solve-problem/-4.2y%2B2.1%20%3E%20%20-2.52

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3 years ago
WILL GIVE BRAINLIEST
Papessa [141]
<span>the particle's initial position is at t=0, x = 0 - 0 + 4 = 4m

velocity is rate of change of displacement = dx/dt = d(t^3 - 9t^2 +4)/dt
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