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3 years ago

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Which type of data would be best displayed in a dot plot

1 answer:

Artyom0805 [142]3 years ago

3 0

Answer:

The number of miles traveled by a dental bus each month.

Step-by-step explanation:

The dot plot is a graph that is used in statistics to represent data. The dot plot are used for unvariate data. This is the data that has only one variable that us being measured. The type of plot is very useful if there is only one variable and the variable is categorical and can be quantified.

Categorical variables can be organized and split into categories. On the other hand, quantitative variables can be measured and have numerical values. The population, shoe size, number of physician visits, are all examples of quantitative variables.

The dots represents the frequency of one thing taking place at a particular time, for example, the number of miles traveled by the bus each day of the month.

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Choose the correct simplification of the expression (2x-6)(3x^2-3x-6)

timama [110]

Answer:

A. 6x^3 - 24x^2 + 6x + 36.

Step-by-step explanation:

(2x - 6)(3x^2 - 3x - 6)

= 2x(3x^2 - 3x - 6) - 6(3x^2-3x-6)

= 6x^3 - 6x^2 - 12x - 18x^2 + 18x + 36

Simplifying like terms:

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3 years ago

Read 2 more answers

A chemist examines 12 sedimentary samples for bromide concentraction. The mean bromide concentration for the sample date is 0.43

Umnica [9.8K]

Answer:

a) $z = 1.645$

b) Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

Step-by-step explanation:

Population is approximately normal, so we can find the normal confidence interval.

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$ . This is the critical value, the answer for a).

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.645*\frac{0.0325}{\sqrt{12}} = 0.015$

The lower end of the interval is the sample mean subtracted by M. So it is 0.437 - 0.015 = 0.422cc/m³.

The upper end of the interval is the sample mean added to M. So it is 0.437 + 0.015 = 0.452 cc/m³.

b)

Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

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3 years ago

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Yakvenalex [24]

Answer:

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