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vovangra [49]
3 years ago
10

3c+2d=2;d=4 step by step

Mathematics
1 answer:
mina [271]3 years ago
6 0
Hi there!

3c + 2d = 2 for d = 4
3c + 2(4) = 2
3c + 8 = 2
Subtract 8 to both sides
3c + 8 - 8 = 2 - 8
3c = -6
Divide both sides by 3
3c/3 = -6/3
c = -2

I hope I helped!
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2 years ago
If elephant grass grows <br> 2 1/5 inches a day, how many inches will it grow in 6 days?
wel

Answer:

13.2 or 13 1/5 inches

Step-by-step explanation:

2 1/5 in/day * 6 days = 13.2 or 13 1/5 inches

OR

  2 1/5 in

+ 2 1/5 in

+ 2 1/5 in

+ 2 1/5 in

+ 2 1/5 in

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6 0
2 years ago
I need help pls due tomorrow pls I just need part B done plsss
lara [203]

Part A

1 day = 1/4 hours of practice

7 days = 7/4 hours of practice (multiply both sides by 7)

1 week = 7/4 hours of practice

1 week = (4+3)/4 hours of practice

1 week = (4+3)/4 hours of practice

1 week = (4/4)+(3/4) hours of practice

1 week = 1+(3/4) hours of practice

1 week = 1 & 3/4 hours of practice

side note: 1 & 3/4 = 1.75

=======================================

Part B

Take the result from part A, and multiply it with 60

So we'll have 60 times 1&3/4 on the left side on the first line, then 60*(1+3/4) on the right side of this same line.

The rest of the lines look like this

(60*1) + (60*3/4)

60 + 60*3/4

60 + 180/4

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105 minutes

8 0
3 years ago
Suppose g (x) is increasing and concave up everywhere and g(A)=7, gprime(A)=13, h=.01
rewona [7]
First we need a point (x,y) : (A, 7) 
<span>Now slope (from f'(A)) = 15 </span>
<span>Next, the equation (using point slope formula) </span>

<span>y - 7 = 15 (x -A) </span>
<span>y = 15 (x - A) + 7 </span>

<span>Now in the x spot we put 'A-.01' </span>
<span>y = 15 ( A - .01 - A) +7= 15(-.01) +7 = -.15+ 7 = 6.85 
hope this helps</span>
8 0
3 years ago
How do you solve 3 1/2- 2 2/5
Veseljchak [2.6K]
You would first have to find common denominators for the fractions. In this case it would be 10. So your new equation would be 3 5/10 - 2 4/10. Once you do this you can then subtract and solve getting the answer of 1 1/10
5 0
3 years ago
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