Answer:
95% confidence interval for the mean number of months is between a lower limit of 6.67 months and an upper limit of 25.73 months.
Step-by-step explanation:
Confidence interval is given as mean +/- margin of error (E)
Data: 5, 15, 12, 22, 27
mean = (5+15+12+22+27)/5 = 81/5 = 16.2 months
sd = sqrt[((5-16.2)^2 + (15-16.2)^2 + (12-16.2)^2 + (22-16.2)^2 + (27-16.2)^2) ÷ 5] = sqrt(58.96) = 7.68 months
n = 5
degree of freedom = n-1 = 5-1 = 4
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (t) corresponding to 4 degrees of freedom and 5% significance level is 2.776
E = t×sd/√n = 2.776×7.68/√5 = 9.53 months
Lower limit of mean = mean - E = 16.2 - 9.53 = 6.67 months
Upper limit of mean = mean + E = 16.2 + 9.53 = 25.73 months
95% confidence interval is (6.67, 25.73)
Answer:
Copy all that then paste it to Google and there is a site that I found the answer on but I can't copy it it's to long.
In order to write

as a percentage, we must first convert the fraction into a decimal. We can do that simply by dividing.
35 / 20 = 1.75
In order to convert a fraction to a decimal, we must multiply it by 100
1.75 * 100 = 175%

as a percentage is 175%.
Hope that helped =)
I think you divide 24 by 8 which = 3 and then times 3•3 which equals 9 so I think that 9 students out of 24 ride the bus
If this is a graph, I attached the file.
The minimum is (122.222, 3277.778)
The y intercept is (0,10000)
The graph: .45x^2-110x+10000