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Tcecarenko [31]

2 years ago

15

The blades of a helicopter's propeller are perpendicular and congruent. The distance between consecutive blade tips is 24 feet.

Find the length (b) of each blade.

1 answer:

Leno4ka [110]2 years ago

7 0

Check the picture below.

now, recall, both blades are congruent, thus a = b, so c² = a² + b² -> c² = b² + b².

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Find the constant of variation k for the inverse variation. Then write an equation for the inverse variation. Y=4.5 when x = 3

Nookie1986 [14]

$\bf \qquad \qquad \textit{inverse proportional variation}\\\\
\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad y=\cfrac{k}{x}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\textit{we also know that }
\begin{cases}
y=4.5\\
x=3
\end{cases}\implies 4.5=\cfrac{k}{3}\implies 4.5(3)=k
\\\\\\
13.5=k\qquad therefore\qquad \boxed{y=\cfrac{13.5}{x}}$

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2 years ago

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dsp73

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Nesterboy [21]

Answer:

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Step-by-step explanation:

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3 years ago

Determine whether the given lengths can be sides of a right triangle. Which of the following are true statements. A.The lengths

Stels [109]

Answer:

Given sides 12, 16 and 20 can be the sides of right triangle.

Step-by-step explanation:

Sides of right triangle always follow the Pythagoras theorem.

i.e $(base)^2 + (Height)^2 = (Hypotenuse)^2$

For the given Lengths 7, 40 and 41

We need to check if

$7^2 + 40^2 =41^2 \\or\\ 7^2 + 40^2 \neq41^2$

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That means, $\\ 7^2 + 40^2 \neq 41^2$

hence 7,40 and 41 can not be the sides of right triangle.

Next,

Given sides 12,16 and 20.

Again follow the similar process used in the above problem.

$12^2 + 16^2 =400\\And \\20^2 = 400\\Since 12^2 + 16^2 = 20^2$

Therefore given sides 12,16 and 20 can be the sides of right triangle.

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