Given:
m(ar QT) = 220
m∠P = 54
To find:
The measure of arc RS.
Solution:
PQ and PT are secants intersect outside a circle.
<em>If two secants intersects outside a circle, then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs.</em>


Multiply by 2 on both sides.


Subtract 220 from both sides.


Multiply by (-1) on both sides.


The measure of arc RS is 112.
Answer:
a = 16
w = 125
x = 120
y = 55
Step-by-step explanation:
<u>FINDING 'a'</u>
31 = a + 46 / 2
62 = a + 46
16 = a
<u>FINDING 'w'</u>
* This section looks Non-Isosceles trapezoid so I will be following the rule according it
w + 55 = 180
w = 125
<u>FINDING 'y'</u>
y = 55
- Because of corresponding angles
<u>FINDING 'x'</u>
* In this case it looks like we are still dealing w/ an non-isosceles trapezoid.
x + 60 = 180
x = 120
Hope this helped ^^
(Please inform me of any mistakes or misunderstandings!)
Answer:
Hi there.....
Step-by-step explanation:
This is ur answer......
1, 3, 5, 7, 9, 11, 13, 15.................39
Therefore the total sum = 400
hope it helps you,
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Answer:
11/2n+-1/2p-2
Step-by-step explanation:
simplification