The presence of a large population of sludgeworms indicates water depleted of oxygen and a high level of organic pollution.
The sludgeworms Tubifex is harvested and sold as tropical fish food since it is common near sewer outlets and serves as a sign of water or organic pollution. Polychaetes are crucial in rearranging the silt on the ocean floor.
Organic contamination happens when too much organic material, such sewage or manure, gets into the water.
There will be more decomposers and sludgeworms in a pond as the organic content accumulates. These decomposers and sludgeworms develop quickly and consume a lot of oxygen as they do so.
Hence, Sludgeworms are a sign of an abundance of oxygen-depleted water and significant levels of organic pollutants.
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- Iron is in limited amount, limiting reagent
- The theoretical yield of iron(III) oxide formed is 27.1 grams.
Given:
The reaction between iron and dioxygen at high temperatures to form iron(III) oxide.
![4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)](https://tex.z-dn.net/?f=4Fe%28s%29%2B3O_2%28g%29%5Crightarrow%202Fe_2O_3%28s%29)
To find:
- The limiting reagent
- The theoretical yield of iron(III) oxide formed when Suppose 19.1 g
of iron is reacted with 17.9 g of oxygen.
Solution:
- The mass of iron = 19.1 g
- The moles of iron
![=\frac{19.1 g}{55.845 g/mol}=0.342 mol](https://tex.z-dn.net/?f=%3D%5Cfrac%7B19.1%20g%7D%7B55.845%20%20g%2Fmol%7D%3D0.342%20mol)
- The mass of dioxygen = 19.1 g
- The moles of dioxygen
![=\frac{17.9 g}{15.999g/mol}=1.12 mol](https://tex.z-dn.net/?f=%3D%5Cfrac%7B17.9%20g%7D%7B15.999g%2Fmol%7D%3D1.12%20mol)
![4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)](https://tex.z-dn.net/?f=4Fe%28s%29%2B3O_2%28g%29%5Crightarrow%202Fe_2O_3%28s%29)
According to reaction, 4 moles of iron reacts with 3 moles of dioxygen then 0.342 moles of iron will react with:
![=\frac{3}{4}\times 0.342 mol=0.2565 mol](https://tex.z-dn.net/?f=%3D%5Cfrac%7B3%7D%7B4%7D%5Ctimes%200.342%20mol%3D0.2565%20mol)
0.2465 moles of dioxygen will react with 0.342 moles of iron which means that:
- Iron is in limited amount, limiting reagent
- dioxygen is in an excessive amount, excessive reagent.
- The amount of iron(III) oxide formed will depend upon moles of iron.
![4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)](https://tex.z-dn.net/?f=4Fe%28s%29%2B3O_2%28g%29%5Crightarrow%202Fe_2O_3%28s%29)
According to reaction, 4 moles of iron gives 2 moles of iron (III) oxide, then 0.342 moles of iron will give:
![=\frac{2}{4}\times 0.342 mol= 0.171 \text{mol of }Fe_2O_3](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2%7D%7B4%7D%5Ctimes%200.342%20mol%3D%200.171%20%5Ctext%7Bmol%20of%20%7DFe_2O_3)
The theoretical yield of 0.171 moles of iron(III) oxide:
![=0.171 mol\times 159.69 g/mol=27.1 g](https://tex.z-dn.net/?f=%3D0.171%20mol%5Ctimes%20159.69%20g%2Fmol%3D27.1%20g)
The theoretical yield of iron(III) oxide formed is 27.1 grams.
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Answer:
Model
Theory
Ellipse
Explanation:
Stan One Direction for better grade
Answer:
Answer below (in explanation)
Explanation:
First find the average atomic mass of the element in question (on the periodic table)
Set up the relative abundance formula: (M1)(x) + (M2)(1-x) = M(E)
Where M1 = Mass of the first isotope, X = Relative abundance, M2 = mass of the second isotope, M(E) = Atomic mass of the element
Plug in your values (i'll use nitrogen as an example) :
(background info: The mass of one isotope, nitrogen-14, is 14.003 amu and another isotope, nitrogen-15, is 15.000 amu, find the relative abundance of the isotopes.
14.003x + 15.000(1-x) =14.007
Use algebra and solve for X. First use distributive property, combine like terms, and solve for X.
It would equal X = 0.996. Multiply by 100 to get a proper percentage and the percentage abundance of Nitrogen-14 is 99.6%
This way of solving is limited to 2 isotopes only.
Done
Answer:
La fuerza resultante o de reacción por parte de la pared es igual a cero
Explanation:
Aunque se aplique una fuerza de 13 kgf sobre la pared ,esta fuerza no es lo suficiente para que se mueva por lo tanto la pared o el objeto al que se le aplica la fuerza está en equilibrio estático.
El que el objeto o la pared esté en equilibrio estático quiere decir que la resultante de las fuerzas que actúan sobre el objeto es cero.