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Andreas93 [3]
2 years ago
8

Which of the following takes place during a redox reaction? A. Electrons are gained only. B. Electrons are lost only. C. Electro

ns are both gained and lost. D. Electrons are neither gained nor lost.
Chemistry
2 answers:
Delvig [45]2 years ago
8 0

The correct statement regarding the redox reaction is

\boxed{{\text{C}}{\text{. Electrons are both gained and lost}}}

Further Explanation:

<u>Redox reaction:</u>

Redox is a term that is used collectively for the reduction-oxidation reaction. It is a type of chemical reaction in which the oxidation states of atoms are changed. In this reaction, both reduction and oxidation are carried out simultaneously. Such reactions are characterized by the transfer of electrons between the species involved in the reaction.

The process of <em>gain of electrons </em>or the decrease in the oxidation state of the atom is called <em>reduction</em> while that of <em>loss of electrons </em>or the increase in the oxidation number is known as <em>oxidation</em>. In redox reactions, one species lose electrons and the other species gain electrons. The species that lose electrons and itself gets oxidized is called as a reductant or reducing agent.The species that gains electrons and gets reduced is known as oxidant or oxidizing agent. The presence of redox pair or redox couple is a must for the redox reaction.

The general representation of a redox reaction is,

{\text{X}}+{\text{Y}}\to{{\text{X}}^ + }+{{\text{Y}}^ - }

The oxidation half-reaction can be written as:

{\text{X}}\to{{\text{X}}^ + }+{e^ - }

The reduction half-reaction can be written as:

{\text{Y}}+{e^ - }\to {{\text{Y}}^ - }

Here, X is getting oxidized and its oxidation state changes from  to +1 whereas Y is getting reduced and its oxidation state changes from 0 to -1. Hence, X acts as the reducing agent whereas Y is an oxidizing agent.

In redox reactions, both reduction and oxidation take place simultaneously. This implies the gain and loss of electrons also proceed at the same time. So electrons are both gained and lost simultaneously in redox reactions. Hence statement C is correct while the others are incorrect.

Learn more:

1. Best cleaning agent for burned-on grease: brainly.com/question/3789105

2. Oxidation and reduction reaction: brainly.com/question/2973661

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Redox reactions

Keywords: redox reaction, oxidation, reduction, reductant, oxidant, reducing agent, oxidizing agent, electrons, redox pair, redox couple, oxidation state, oxidized, reduced, simultaneously.

zhannawk [14.2K]2 years ago
5 0
I believe the correct answer from the choices listed above is option C. Electrons are both gained and <span>lost during a redox reaction. From the name itself "redox" or reduction-oxidation, it must be that something has reduced and another has gained that something.</span>
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n = mass / Mr
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5 0
3 years ago
A 3.31-g sample of lead nitrate, Pb(NO3)2, molar mass = 331 g/mol, is heated in an evacuated cylinder with a volume of 2.53 L. T
Dahasolnce [82]

Answer:

0.486atm is the pressure of the cylinder

Explanation:

1 mole of Pb(NO₃)₂ descomposes in 4 moles of NO2 and 1 mole of O2. That is 1 mole descomposes in 5 moles of gas.

To find the pressure of the cylinder, we need to find moles of gas produced, and using general gas law we can determine the pressure of the gas:

<em>Moles Pb(NO₃)₂ and moles of gas:</em>

3.31g * (1mol / 331g) = 0.01 moles of Pb(NO₃)₂.

That means moles of gas produced is 0.05 moles.

<em>Pressure of the gas:</em>

Using PV = nRT

P = nRT/V

<em>Where P is pressure (Incognite)</em>

<em>V is volume (2.53L)</em>

<em>R is gas constant (0.082atmL/molK)</em>

<em>T is absolute temperature (300K)</em>

And n are moles of gas (0.05 moles)

P = 0.05mol*0.082atmL/molK*300K / 2.53L

P = 0.486atm is the pressure of the cylinder

3 0
3 years ago
HELP NOW FIRST=BRANILYEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
cestrela7 [59]

Answer:

the answer is c. their atomic masses are different clearly because an atom of gold has 79 protons and the atom can be divided multiple times. An atom of silver has an atomic number of 47. 47 electrons. Clearly different. Hope it helps :)

Explanation:

3 0
3 years ago
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20 mL of 80°C water is mixed with 20 mL of 0°C water in a perfect calorimeter. What is the final temperature?
dedylja [7]
To calculate for the final temperature, we need to remember that the heat rejected should be equal to the absorbed by the other system. We calculate as follows:

Q1 = Q2
(mCΔT)1 = (mCΔT)2

We can cancel m assuming the two systems are equal in mass. Also, we cancel C since they are the same system. This leaves us,

 (ΔT)1 = (ΔT)2
(T - 80) = (0 - T)
T = 40°C
8 0
3 years ago
Someone please help! this is the last question<br>I only need help with B.<br><br>​
ludmilkaskok [199]

1. mol ratio of Al(NO₃)₃ : Na₂CO₃ = 2 : 3

2. Na₂CO₃ as a limiting reactant

<h3>Further explanation</h3>

Given

Reaction

2 Al(NO₃)₃ + 3 Na₂CO₃ → Al₂(CO₃)₃ + 6 NaNO₃

Required

mol ratio

Limiting reactant

Solution

The reaction coefficient in the chemical equation shows the mole ratio of the components of the compound involved in the reaction (reactants and products)

1. From the equation mol ratio of Al(NO₃)₃ : Na₂CO₃ = 2 : 3

2. mol : coefficient of Al(NO₃)₃ : Na₂CO₃ = 2 mole/2 : 2 mole/3 = 1 : 0.67

Na₂CO₃ as a limiting reactant (smaller)

6 0
2 years ago
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