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4 years ago

If the contents of a cell have a solute concentration of 0.04 percent which of these solutions would cause it to swell?

2 answers:

4 0

"0.01 percent solute concentration" is the solution among the choices given in the question that <span>would cause it to swell. The correct option among all the options that are given in the question is the fourth option or option "D". I hope that the answer has actually come to your great help.</span>

Akimi4 [234]4 years ago

3 0

Answer : Option D) 0.01 percent solute concentration

Explanation : The contents of a cell if has the solute concentration as 0.04 percent then it should have much lesser concentration that the cell, then only it will allow the cell to swell. Because of the solutions with a lower osmotic pressure than a cell fluid solution concentration, can make it swell.

Hence,the answer will be 0.01 percent of solute concentration.

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Ahhhh someone help me with this

Paladinen [302]

Answer:

3.6g

Explanation:

2 moles of water gives 1 mole of oxygen

2(h2o)=1(o2)

2(molar mass of h2o)=1(molar mass of oxygen molecule)

2(18)=1(16×2)

36=32

3.6=x

cross multiply

3.6×32=36× x

115.2=36x

x=115.2÷36

x=3.6g

5 0

3 years ago

How many moles of N₂ are essential for generating 0.08 moles of Li₃N in the given reaction?

joja [24]

Each mole of N₂ generates 2 moles of Li₃N. Thus,
0.08 moles of Li₃N will require:
0.08 / 2
= 0.04 moles of N₂

The second option is correct.

4 0

3 years ago

If h is written in scientific notation but its coefficient is not 1, what do you need to calculate ph

Darya [45]

Are there any options for this question

4 0

3 years ago

Describe how you would prepare approximately 2 l of 0.050 0 m boric acid, b(oh)3.

Elenna [48]

The given concentration of boric acid = 0.0500 M

Required volume of the solution = 2 L

Molarity is the moles of solute present per liter solution. So 0.0500 M boric acid has 0.0500 mol boric acid present in 1 L solution.

Calculating the moles of 0.0500 M boric acid present in 2 L solution:

$2 L * \frac{0.0500 mol B(OH)_{3} }{1 L} = 0.100 mol B(OH)_{3}$

Converting moles of boric acid to mass:

$0.100 mol B(OH)_{3} * \frac{61.83 g}{mol B(OH)_{3}} = 6.183 g$

Therefore, 6.183 g boric acid when dissolved and made up to 2 L with distilled water gives 0.0500 M solution.

5 0

3 years ago

What type of cells are in mitosis?

Dmitriy789 [7]

Answer:

Meiosis is a process where a single cell divides twice to produce four cells containing half the original amount of genetic information. These cells are our sex cells – sperm in males, eggs in females. ... These four daughter cells only have half the number of chromosomes? of the parent cell – they are haploid.

Explanation:

Basically haploid cells

3 0

4 years ago