All categories

3 years ago

13.

Mathematics

2 answers:

RUDIKE [14]3 years ago

8 0

Answer: $2,596 cm^2$

Step-by-step explanation:

Given dimensions of rectangular prism :

length: 8 cm

width: 13 cm

height: 10.5 cm

If all the dimensions of the prism are doubled, then the new dimensions will be:

length: 16 cm

width: 26 cm

height: 21 cm

The surface area of rectangular prism is given by :-

$S.A.=2(lw+wh+hl)\\\\\Rightarrow\ S.A.=2(16*26+26*21+21*16)\\\\\Rightarrow\ S.A.=2,596 cm^2$

Hence, its new surface area $2,596 cm^2$

svetlana [45]3 years ago

7 0

The answer is 2,596 so it would be C

You might be interested in

What is the value of x and y?

Pavel [41]

Answer:

$x=\boxed{2}$

$y=\boxed{4}$

Step-by-step explanation:

$\begin{cases} y= 6x-8... (1)\\\\y=-3x+10...(2)\end{cases}$

From equations (1) & (2), we find:

6x - 8 = - 3x +10

$\therefore 6x+3x = 8+10$

$\therefore 9x = 18$

$\therefore x =\frac{18}{9}$

$\therefore x = 2$

Plug x = 2 in equation (1)

y = 6(2)-8 = 12-8 =4

So,

$x=\boxed{2}$

$y=\boxed{4}$

6 0

3 years ago

Read 2 more answers

EThe graph of a quadratic function passes through the points (6,0) and (p,0). The maximum point

MA_775_DIABLO [31]

Answer:

p = - 5

Step-by-step explanation:

The vertex of the function is (0.5, 30.25 )

Since the roots are (6, 0) and (p, 0) then the axis of symmetry is vertical

with equation x = 0.5

The axis of symmetry passes through the midpoint of the roots, thus

$\frac{6+p}{2}$ = 0.5 ( multiply both sides by 2 )

6 + p = 1 ( subtract 6 from both sides )

p = - 5

6 0

3 years ago

WILL GIVE BRAINLIEST!!! How many terms are in the geometric sequence having a first term of 2, a last term of 32, and a common r

Elza [17]

Answer:

Step-by-step explanation:

first term a= 2

last term tn= 32

common ratio r= -2

number of terms

= tn=ar^n-1

32 = 2*(-2)^n-1

divide both sides by 2

32/2 = 2*(-2)^n-1/2

16 = (-2)^n-1

Then...use 16 in the power of 2

(-2)^4 = (-2)^n-1

The bases (-2), cancels out

so we have: 4 = n-1

collect like terms

4-1 = n

3 = n

n= 3

7 0

3 years ago

Solve the following ODE's: c) y* - 9y' + 18y = t^2

Nastasia [14]

Answer:

y = $C_1e^{3t}+C_2e^{6t}$ + $\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

Step-by-step explanation:

y''- 9 y' + 18 y = t²

solution of ordinary differential equation

using characteristics equation

m² - 9 m + 18 = 0

m² - 3 m - 6 m+ 18 = 0

(m-3)(m-6) = 0

m = 3,6

C.F. = $C_1e^{3t}+C_2e^{6t}$

now calculating P.I.

$P.I. = \frac{t^2}{D^2 - 9D +18}$

$P.I. = \dfrac{t^2}{(D-3)(D-6)}\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1-\frac{D}{6})^{-1}(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1+\frac{D}{6}+\frac{D^2}{36}+....)(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(1+\frac{D}{3}+\frac{D^2}{9}+....)(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$