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Dominik [7]
3 years ago
8

What is 5.4 times 7/4 how do you work that out what is the answer

Mathematics
2 answers:
inn [45]3 years ago
4 0
\frac{7*5.4}{4}     You can either turn 5.4 into a fraction and cross multiply or you can multiply 5.4 and 7 over 4 and you'd get \frac{37.8}{4}       which simplifies to 9.45.
Zarrin [17]3 years ago
4 0

Answer:  The required value is 9.45.

Step-by-step explanation:  We are given to find the following value :

"5.4 times \dfrac{7}{4}."

To work out the given problem, first we convert the decimal into a fraction. And, then we will multiply both the fractions.

The evaluation is as follows :

E\\\\=5.4\times\dfrac{7}{4}\\\\\\=\dfrac{54}{10}\times\dfrac{7}{4}\\\\\\=\dfrac{27\times7}{20}\\\\\\=\dfrac{189}{20}\\\\=9.45.

Thus, the required value is 9.45.

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Answer:

v_{o} \approx 31.247\,mph

Step-by-step explanation:

The deceleration experimented by the car is the product of kinetic coefficient of friction and gravitational constant:

a = \mu_{k}\cdot g

a = (1.02)\cdot \left(32.174\,\frac{ft}{s^{2}} \right)

a = 32.817\,\frac{ft}{s^{2}}

The initial speed is computed from the following kinematic expression:

v^{2} = v_{o}^{2} - 2\cdot a \cdot \Delta s

v_{o} = \sqrt{v^{2}+2\cdot a\cdot \Delta s}

v_{o} = \sqrt{\left(0\,\frac{ft}{s} \right)^{2}+2\cdot \left(32.817\,\frac{ft}{s^{2}} \right)\cdot (32\,ft)}

v_{o}\approx 45.829\,\frac{ft}{s}

v_{o} \approx 31.247\,mph

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3 years ago
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Step-by-step explanation:

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3 years ago
11.3 x 3 = 28.25 please show the formula​
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4 0
3 years ago
8x + 34. What does X equal
rosijanka [135]

Answer: x=-4.25

Step-by-step explanation:

First you put it in to y= mx+b form.

0=8x+34

Then you subtract 34 from both sides

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Then you divide 8 from both sides

Leaving you with

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