just use what you know about this stuff
(a+36d)/(a+20d) = (a+55d)/(a+36d)
(a+36d)^2 = (a+55d)(a+20d)
a^2+72ad+1296d^2 = a^2+75ad+1100d^2
3ad = 196d^2
3a = 196d
That is, for any value of n,
a=196n
d=3n
So, there is no unique solution.
If n=1, then a=196 and d=3. The terms are
196+20*3 = 256
196+36*3 = 304
196+55*3 = 361
304/256 = 361/304
You can easily verify that it works for any value of n.
Answer:
A
Step-by-step explanation:
It looks like M is composed of all real numbers and that U = R also means its composed of all real numbers. This means that M and U are equal and both are composed of all real numbers.
To define the complement of M, it includes all values which are not in M. However, since M already has all real numbers and U doesn't have any values that M doesn't then the complement is nothing. It is an empty set with no items in it. This means A is the correct answer.
sequences can be expressed in terms of the nth term of the sequence. In this case, the nth term = 2n. To find the 1st term, put n = 1 into the formula, to find the 4th term, replace the n's by 4's: 4th term = 2 × 4 = 8.
Does this help?
Divide 5 by 89 and you get a=17.8
