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Dovator [93]
3 years ago
12

(NO TROLLS 3 TIMES THE CHARM) In △ABC, AB = BC = 20 and DE ≈ 9.28. Approximate BD.

Mathematics
2 answers:
andreev551 [17]3 years ago
3 0

Answer:

≈ 5.36

Step-by-step explanation:

If we have a triangle in which the angle measure of it being broken down are the same, that means that the legs in which the angle measures are the same will have the same length.

If we already know that DE ≈ 9.28, then we can subtract this from 20 and divide by two to get BD, which is equal to EC.

20-9.28=10.72\\10.72\div2=5.36

However, I'm not 100% sure about this answer.

Hope this helped (and I hope I'm right)

atroni [7]3 years ago
3 0

Answer:

5.3589 or 5.36

Step-by-step explanation:

tan (15) = x / 20

x = 40 - 34.64

x = 5.36

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The point (7, 4) lies on a circle centered at the origin. Write the equation of the circle and state the radius.
k0ka [10]

Given:

The point (7, 4) lies on a circle centered at the origin.

To find:

The equation of the circle and the radius of the circle.

Solution:

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The point (7, 4) lies on a circle centered at the origin. So, the distance between the points (7,4) and (0,0) is equal to the radius of the circle.

r=\sqrt{(0-7)^2+(0-4)^2}

r=\sqrt{(-7)^2+(-4)^2}

r=\sqrt{49+16}

r=\sqrt{65}

The standard form of the circle is

(x-h)^2+(y-k)^2=r^2            ...(i)

Where, (h,k) is the center of the circle and r is the radius of the circle.

Putting h=0, k=0 and r=\sqrt{65} in (ii), we get

(x-0)^2+(y-0)^2=(\sqrt{65})^2

x^2+y^2=65

Therefore, the equation of the circle is x^2+y^2=65 and its radius is r=\sqrt{65}.

7 0
3 years ago
What is x in the equation, x - 32 = 68 - 4x
shepuryov [24]
X - 32 = 68 - 4x
+32 +4x       + 32 +4x
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---     -----
 5        5
x = 20
4 0
3 years ago
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6 0
3 years ago
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Yulet rolls 2 fair dice and adds the results from each. Work out the probability of getting a total of 7.
Pie

Answer:

the answer is 1/6

Step-by-step explanation:

Let (a,b) denote a possible outcome of rolling the two die, with a the number on the top of the first die and b the number on the top of the second die. Note that each of a and b can be any of the integers from 1 through 6. Here is a listing of all the joint possibilities for (a,b):  

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

With the above declaration, the outcomes where the sum of the two dice is equal to 7 form an event. If we call this event E, we have

E={(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)}.

so Possibilities(P) of having Event (E)

P(E)=6/36

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6 0
4 years ago
15 ounces in water bottle 8.5 was drunk how many left
Levart [38]

Answer:

6.5 ounces

Step-by-step explanation:

Hope this helps.

3 0
3 years ago
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