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oksian1 [2.3K]
3 years ago
8

Cari drew a line that was 9 inches long. She divided the line into 10 equal-length segments.

Mathematics
2 answers:
vivado [14]3 years ago
8 0
Hello!

You divide how long the line is by the amount of segments

9 / 10 = 0.9

The answer is 0.9 inches long

Hope this helps!
viktelen [127]3 years ago
8 0
Answer: 0.9 inches

Explanation:

Total length is cut into 10 pieces.

====> 10 pieces = 9 inches

====> 1 piece = 9 ÷ 10 = 0.9 inches.
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What’s the answer ?
mezya [45]

Ans should be 133°

Step-by-step explanation:

As we know..

sum of internal angles of a hexagon is 720°

So,

120+130+150+97+90+x=720

solving this we obtain value of x as 133°

3 0
3 years ago
The price of a candy bar is $1.53. If this is three cents more than triple the price ten years ago, how much did the candy bar c
Tamiku [17]

Answer:

$0.51

Step-by-step explanation:

Hello! Using what we know, the price of the candy bar at the moment is $1.53, triple the price from 10 years ago. So, triple cents would technically be $0.03. We divide $1.53 and $0.03 and get 51! But, it would not make sense for the price ten years ago to be 51 then go to 1.53, so we make 51 a decimal, 0.51. We can check to see if this correct, by doing 0.51 times 3, because the price is tripling, and we get $1.53! Have an awesome day! :)

6 0
3 years ago
What is the value of a?<br> a+36°<br> a-27°
aliya0001 [1]

Answer:

hope this will help you more

6 0
3 years ago
-2x + 4x = -4 + 0<br> What is the answer?
lys-0071 [83]

Answer:

x = -2

Step-by-step explanation:

-2x + 4x = -4 + 0

2x = -4

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Hope this helps.

8 0
3 years ago
Read 2 more answers
If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei
MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

 The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is {11 \choose 3} = 165 . As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

4 0
3 years ago
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