A trig identity is <span>asinucosu=<span>a/2</span>sin(2u)</span>So you can write your equation as<span>y=sin(x)cos(x)=<span>1/2</span>sin(2x)</span>Use the crain rule here<span><span>y′</span>=<span>d/<span>dx</span></span><span>1/2</span>sin(2x)=<span>1/2</span>cos(2x)<span>d/<span>dx</span></span>2x=cos(2x)</span>The curve will have horizontal tangents when y' = 0.<span><span>y′</span>=0=cos(2x)</span>On the interval [-pi, pi], solution to that is<span><span>x=±<span>π4</span>,±<span><span>3π</span>4</span></span></span>
To solve this you want to plug in your x's and y's to see if they match.
A. 3(11)-4=33-4=29 and 29 is not equal to 5 so A is not a solution
B.3(5)-4=15-4=11=11 3(3)-4=9-4=5 and 5 is not equal to 2 so B is not a solution
C. 3(2)-4= 6-4=2 2 is not equal to 3 so C is not a solution
D is the answer. 3(5)-4=11 and 3(2)-4= 2
Answer:
that box means the angle is 90 degrees.
Step-by-step explanation:
if you need anymore help just message me
The correct answer is B because the data points are too scattered
Hope this helped :)
Answer: 
Step-by-step explanation:
Given : To avoid detection at customs, a traveler places 6 narcotic tablets in a bottle containing 9 vitamin tablets that are similar in appearance.
Proportion of success : 
Sample size taken by customs official : n= 3
Let x be a binomial variable that represents the tablets in the bottle.
Using Binomial probability formula :-
The probability that the traveler will be arrested for illegal possession of narcotics =
![1-^3C_0(\dfrac{2}{3})^0(1-\dfrac{2}{3})^3\\\\=1-(1)(1)(\dfrac{1}{3})^3\ [\becuase ^nC_0=1]\\\\=1-\dfrac{1}{27}=\dfrac{26}{27}](https://tex.z-dn.net/?f=1-%5E3C_0%28%5Cdfrac%7B2%7D%7B3%7D%29%5E0%281-%5Cdfrac%7B2%7D%7B3%7D%29%5E3%5C%5C%5C%5C%3D1-%281%29%281%29%28%5Cdfrac%7B1%7D%7B3%7D%29%5E3%5C%20%5B%5Cbecuase%20%5EnC_0%3D1%5D%5C%5C%5C%5C%3D1-%5Cdfrac%7B1%7D%7B27%7D%3D%5Cdfrac%7B26%7D%7B27%7D)
Hence, the probability that the traveler will be arrested for illegal possession of narcotics =
