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3 years ago

Which function below has the lowest y-intercept?

Mathematics

2 answers:

Arte-miy333 [17]3 years ago

8 0

If f(x) is given with points (0,5) and (4,3), it can be easily plotted in a coordinate system (see .jpeg image in attachment).
If g(x) is a function defined by text:
Kyle started the summer having read 3 books but plans to read 6 books per month over the summer.
Then, g(x) is given with:
g(x) = 6*x+3 (3 books read already, and 6 books will be read each month).
h(x) is already given with:
h(x)=3*x+4
These all three functions are plotted in coordinate system (see the .jpeg image), and it can be seen that the lowest y-intercept has function g(x), and it is the value of 3 on y-axis. Others have 4 (h(x)) and 5 (f(x)).
See the .jpeg image in attachment.

butalik [34]3 years ago

8 0

Here is your answer:

$g(x) = 6 \times x+3\\h(x)=3\times x+4\\\\$

The lowest y-intercept has function g(x) with the value of three the others have four (h(x)) and five (f(x))which would mean that your answer is the second option "g(x)."

Hope this helps!

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Answer:

A.

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Step-by-step explanation:

Given

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Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

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Since a belongs to the x axis and b belongs to the y axis;

$cos\theta$ is calculated as thus

$cos\theta = \frac{a}{r}$

Substitute $r = \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}$

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}}$

Rationalize the denominator

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}$

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

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3 years ago

Can someone help meee please

hoa [83]

Answer:

Equation → 5y = 3y + 6

Value of ST = 15

Step-by-step explanation:

From the picture attached,

In right triangles ΔVST and ΔVUT,

Acute angles ∠SVT ≅ ∠UVT [Given]

TV ≅ TV [By reflexive property of congruence]

ΔVST ≅ ΔVUT [Hypotenuse angle congruence of right triangles]

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Therefore, ST ≅ TU

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Therefore, ST = 5y

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