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olya-2409 [2.1K]
3 years ago
9

Which sample contains particles in a rigid, fixed, geometric pattern?(1) CO2(aq) (3) H2O(ℓ)(2) HCl(g) (4) KCl(s)

Chemistry
1 answer:
Masteriza [31]3 years ago
3 0
KCI (s) contains particles in a rigid, fied, geometric pattern.
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Choose all the answers that apply.
Tresset [83]
<h3>Answer:</h3>

#a.2H2 + O2 → 2H2O

#b. 2S + 3O2 → 2SO3

#d. 2K + 2H2O → H2 + 2KOH

<h3>Explanation:</h3>
  • A balanced chemical equation is one that has equal number of atoms of each element on both sides of the equation.

In this case;

  • 2H2 + O2 → 2H2O - is balanced since it has, 4 hydrogen atoms and 2 oxygen atoms on either sides of the equation.
  • 2S + 3O2 → 2SO3, is balanced. It has 2 sulfur atoms and 6 oxygen atoms on both side of the equation.
  • 2K + 2H2O → H2 + 2KOH, is balanced , 2 potassium atoms, 4 hydrogen atoms and 2 oxygen atoms on both side of the equation.
  • On the other hand, the equations that are not balanced include;
  1. Li + Cl2 → LiCl
  2. 2Fe + Cu(NO3)2 → 2Cu + Fe(NO3)2

This is because the number of atoms of each element is not equal on both side of the equation/

5 0
3 years ago
Read 2 more answers
A/An _____ is described as a flow of charged particles.
azamat

Answer:

B, electric current .........

6 0
3 years ago
Read 2 more answers
Calcium hydroxide is titrated with nitric acid. What volume of 0.0200 M calcium hydroxide is required to neutralize 35.00 ml of
gogolik [260]

Answer:

43.75 ml

Explanation:

Given that the equation of the reaction is;

2HNO3(aq) + Ca(OH)2(aq) ---> Ca(NO3)2(aq) + 2 H20(l)

Concentration of acid CA= 0.05 M

Concentration of base CB = 0.02 M

Volume of acid VA = 35.00ml

Volume of base VB= ???

Number of moles of acid NA= 2

Number of moles of base NB=1

From

CAVA/CBVB= NA/NB

Making VB the subject of the formula;

VB= CAVANB/CBNA

VB= 0.05 × 35 × 1/ 0.02 × 2

VB=1.75 /0.04

VB= 43.75 ml

8 0
3 years ago
The British gold sovereign coin is an alloy of gold and copper having a total mass of 7.988 g, and is 22-karat gold. (a) Find th
jonny [76]

Answer:

(a) Mass of gold = 0.0073223 kg.

(b) V of gold 3.79 x 10⁻⁷ m³ & ∴ V of copper = 7.438 x 10⁻⁸ m³.

(c) The density of the British sovereign coin 17,620 kg/m³.

Explanation:

<em>(a) Find the mass of gold in the sovereign in kilograms using the fact that the number of karats = 24 (mass of gold)/(total mass). </em>

<em></em>

∵ the number of karats = 24 (mass of gold)/(total mass)

the number of karats = 22-karat gold,

mass of gold = ??? g,

total mass = 7.988 g.

<em>∴ mass of gold = (the number of karats)(total mass)/24 =</em> (22)(7.988 g)/(24) = 7.3223 g = <em>0.0073223 kg.</em>

<em></em>

<em>(b) Calculate the volumes of gold and copper, respectively.</em>

∵ Mass of coin = 7.988 g.

∵ mass of gold = 7.3223 g.

∴ mass of Cu = Mass of coin - mass of gold = 7.988 g - 7.3223 g = 0.6657 g = 0.6657 x 10⁻³ kg.

  • To find the volume of Copper and gold, we can use the relation:

<em>V = m/d.</em>

where, V is the volume of the material,

m is the mass of the material,

d is the density of the material.

  • For gold:

Density of gold = 19,320 kg/m³, mass of gold = 0.0073223 kg.

∴ V of gold = m/d = (0.0073223 kg)/(19,320 kg/m³) = 3.79 x 10⁻⁷ m³.

 

  • For copper:

Density of copper = 8,950 kg/m³, mass of copper = 0.6657 x 10⁻³ kg.

∴ V of copper = m/d = (0.6657 x 10⁻³ kg)/(8,950 kg/m³) = 7.438 x 10⁻⁸ m³.

<em>(c) Calculate the density of the British sovereign coin. kg/m³.</em>

  • To find the density of the British sovereign coin, we can use the relation:

<em>d = m/V.</em>

mass of the British sovereign coin = 7.988 g = 0.007988 kg.

Volume of the British sovereign coin = V of gold + V of copper = (3.79 x 10⁻⁷ m³) + (7.438 x 10⁻⁸ m³) = 4.534 x 10⁻⁷ m³.

∴ Density of the British sovereign coin = m/V = (0.007988 kg)/(4.534 x 10⁻⁷ m³) = 17,620 kg/m³.

5 0
3 years ago
Which terms describe a substance that has a low melting point and poor electrical conductivity?
lilavasa [31]
(2) Dull and brittle.
6 0
3 years ago
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