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4 years ago

Write a balanced equation for the following by inserting the correct coefficients.

1 answer:

3 0

In order to write a balanced equation, all you have to do is look at your atoms on each side and make sure there are the same amount present on either side.

K 1 | K 1
OH 1 | OH 3
Al 1 | Al 1
NO3 3 | NO3 1

So what you would need to do is add a coefficient in front of each compound to make sure there is the same amounts on either side. Your equation should look like this at the end:

3KOH(aq) + Al(NO3)3(aq) —-> Al(OH)3(s) + 3KNO3(aq)

Make sure that when you are balancing you keep the polyatomic ions together.

You might be interested in

At standard pressure, which element has a freezing point below standard temperature?

borishaifa [10]

⛄ (4)HG
-This is because it has a freezing point below standard temperature.

5 0

4 years ago

What are some examples of supersaturated solutions? Give 10.

Phantasy [73]

Examples include carbonated water (i.e. soda water); honey; sugar syrup (used in confectionery); supersaturated drug delivery systems. "SDDS"; and sodium acetate solutions prepared from 160 g NaOAc and 30 mL water.

7 0

3 years ago

an aqeous solution of oxalic acid h2c2o4 was prepared by dissolving a 0.5842g of solute in enough water to make a 100 ml solutio

vampirchik [111]

The question is incomplete, here is the complete question:

An aqeous solution of oxalic acid was prepared by dissolving a 0.5842 g of solute in enough water to make a 100 ml solution a 10 ml aliquot of this solution was then transferred to a volumetric flask and diluted to a final volume of 250 ml. How many grams of oxalic acid are in 100. mL of the final solution?

<u>Answer:</u> The mass of oxalic acid in final solution is 0.0234 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ ......(1)

Given mass of oxalic acid = 0.5842 g

Molar mass of oxalic acid = 90 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Molarity of oxalic acid solution}=\frac{0.5842\times 1000}{90\times 100}\\\\\text{Molarity of oxalic acid solution}=0.0649M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated oxalic acid solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted oxalic acid solution

We are given:

$M_1=0.0649M\\V_1=10mL\\M_2=?M\\V_2=250.0mL$

Putting values in above equation, we get:

$0.0649\times 10=M_2\times 250.0\\\\M_2=\frac{0.0649\times 10}{250}=0.0026M$

Now, calculating the mass of glucose by using equation 1, we get:

Molarity of oxalic acid solution = 0.0026 M

Molar mass of oxalic acid = 90 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0026=\frac{\text{Mass of oxalic acid solution}\times 1000}{90\times 100}\\\\\text{Mass of oxalic acid solution}=\frac{0.0026\times 90\times 100}{1000}=0.0234g$

Hence, the mass of oxalic acid in final solution is 0.0234 grams

6 0

4 years ago

How many kilograms of water form when 48 kg of oxygen gas chemically combine with 6 kg of hydrogen gas?

Snezhnost [94]

That would equal 54 kilograms of water. i know it sounds dumb but you have to realize that the weight will not just decrease since that's the units of measure were dealing with

6 0

4 years ago

A block of ice with a total mass of of 25 grams is beginning to melt. How will this physical change affect the mass of the block

NISA [10]

It does not affect the mass, it only affects the outwards appearance of the ice/water.

7 0

4 years ago