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Romashka [77]
3 years ago
7

15 points!

Chemistry
2 answers:
irina [24]3 years ago
7 0

Answer:

65

Explanation:

marshall27 [118]3 years ago
4 0

Answer:

C. To make it possible for others replicate experiment

Explanation:

I GOT IT CORRECT ON THE TEST :)

Have a good day

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A sample of aluminum, which has a specific heat capacity of , is put into a calorimeter (see sketch at right) that contains of w
Oksanka [162]

Complete Question

A sample of aluminum, which has a specific heat capacity of 0.897 JB loc ! is put into a calorimeter (see sketch at right) that contains 200.0 g of water. The aluminum sample starts off at 85.6 °C and the temperature of the water starts off at 16.0 °C. When the temperature of the water stops changing it's 20.1 °C. The pressure remains constant at 1 atm. Calculate the mass of the aluminum sample.

Answer:

M=58g

Explanation:

From the question we are told that:

Heat Capacity H=0.897

Mass of water M=200g

Initial Temperature of Aluminium T_a=85.6

Initial Temperature of Water T_{w1}=16.0

Final Temperature of Water  T_{w2}=16.0

Generally

Heat loss=Heat Gain

Therefore

M*0.897*(85.6-20.1) =200*4.184*(20.1-16)

M=58g

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Bakit mahalaga ang paghahanda ng pambansang badyet sa isang taon?​
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A sample of 28 Mg decays initially at a rate of 53500 disintegrations per minute, but the decay rate falls to 10980 disintegrati
prisoha [69]

Answer : The half life of 28-Mg in hours is, 6.94

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant

t = time passed by the sample = 48.0 hr

a = initial amount of the reactant disintegrate = 53500

a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520

Now put all the given values in above equation, we get

k=\frac{2.303}{48.0}\log\frac{53500}{42520}

k=9.98\times 10^{-2}hr^{-1}

Now we have to calculate the half-life.

k=\frac{0.693}{t_{1/2}}

9.98\times 10^{-2}=\frac{0.693}{t_{1/2}}

t_{1/2}=6.94hr

Therefore, the half life of 28-Mg in hours is, 6.94

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State, in terms of the arrangement of atoms, the difference in hardness between diamond and graphite.
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The difference in hardness between diamond and graphite is that diamond has an ordered arrangement of atoms within its structure that makes it harder and stronger than graphite. This is due to the high pressure and high temperature that it went.

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