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Amanda [17]
3 years ago
8

What is the difference of the medians as a multiple of Megan's interquartile range?

Mathematics
2 answers:
Norma-Jean [14]3 years ago
6 0
From the figure associated to your question (which you did not attach), Amy's median is 40 and Megan's median is 35.

Thus, the difference in medians is given by 40 - 35 = 5.

From the figure, Megan's Q1 is 25 and her Q3 is 40, thus her interquatile range is given by Q3 - Q1 = 40 - 25 = 15.

Therefore, <span>the difference of the medians as a multiple of Megan's interquartile range is given by

Difference in medians = 1/3 (Megan's IQR)
</span>
Fiesta28 [93]3 years ago
4 0

Answer: 1/3

Step-by-step explanation:

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inna [77]

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n+1equal 8

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Rectangle A has a length of 2x + 6 and a width of 3x. Rectangle B has a length of x + 2 and an area of 12 square units greater t
Maurinko [17]
So here is how you solve for the answer.
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7 0
3 years ago
What is ​ BC ​ ? <br><br> Enter your answer in the box.<br><br> units
Vladimir79 [104]

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3 years ago
Let f(x)=3x-6. Is f one-to-one? If it is find f^-1, if not explain why.
beks73 [17]

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Lana71 [14]
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