Sally can paint a room in 99 hours while it takes steve 44 hours to paint the same room. how long would it take them to paint th
2 answers:
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Answer: hello your question is poorly written attached below is the complete question
answer:
attached below
Step-by-step explanation:
using
m^2 - 2m + 10 = 0
m = 2± (√4 - 4(1)(10)) / (2(1)) = 1 ± 3i
Hence the complementary function ; Yc = e^x ( C1 cos3x + C2 sin3x )
attached below is the detailed solution
Answer:
The rate at which the distance between the two cars is changing is;
15.53 ft/sec.
Step-by-step explanation:
To solve the question, we note that
Position of car A 4 s after start of motion, w = 18 ft west,
Position of car B 4 s after start of motion, n = 27 ft north
Therefore
The distance between the two cars at the 4 s instance is
d² = w² + n²
d² = 18² + 27² = 1053 ft² and
d = 32.45 ft
The rate at which the distance between the two cars is changing is given by;
Differentiating both sides of the equation, d² = w² + n², with respect to t as follows.
It is given that the speeds of car A and car B at the 4 second instant are 7 ft/sec and 14 ft/sec, respectively
That is;
and
Substituting the values of speed in the equation of rate of change gives
The rate at which the distance between the two cars is changing = dd/dt = 15.53 ft/sec.