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faust18 [17]
2 years ago
6

Calculate the average rate of change over the interval 2

Mathematics
1 answer:
Morgarella [4.7K]2 years ago
8 0

Answer:

Average rate of change over the interval 2<= x <= 5:

y = 3x + 5:        3

y = 3x^2 + 1:     21

y = 3^x:             78

<u />

Step-by-step explanation:

2<= x <= 5

Average rate of change over the interval 2<= x <= 5:

<u>y = 3x + 5</u>

y(5) = 3(5) + 5 = 20

y(2) = 3(2) + 5 = 11

Average rate of change = (20 - 11)/(5-2) = 9/3 = <u>3</u>

<u />

<u>y = 3x^2 + 1</u>

y(5) = 3(5^2) + 1 = 75 + 1 = 76

y(2) = 3(2^2) + 1= 13

Average rate of change = (76 - 13)/(5-2) = 63/3 = <u>21</u>

<u />

<u>y = 3^x</u>

y(5) = 3^5 = 243

y(2) = 3^2 =9

Average rate of change = (243-9)/(5-2) = 234/3 =<u> 78</u>

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Answer:

<h3><u>7. Ans ;</u></h3>

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<h3><u>8</u><u>.</u><u> </u><u>Ans</u><u> </u><u>;</u></h3>

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<h3><u>7. Ans ;</u></h3>

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So ;

\frac{41}{3}  < 14 <  \sqrt{200}  \\ 13.6 < 14 < 14.1

<h3><u>8. Ans ;</u></h3>

\frac{2}{3}  = 0.66 \\  \sqrt{ \frac{9}{16} }   =   \frac{3}{4}  = 0.75 \\ 0.6 = 0.6

So ;

0.6 <  \frac{2}{3}  <  \sqrt{ \frac{9}{16} }  \\ 0.6 < 0.66 < 0.75

I hope I helped you^_^

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