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zloy xaker [14]
3 years ago
12

The diameter of a cone shaped is 4 in. Its height is 6 in. How much greater is the volume of a cylinder shaped container with th

e same diameter and height? Please show work
Mathematics
1 answer:
nasty-shy [4]3 years ago
5 0

The radius r used in below equations would equal 2in because it is half the given diameter of 4in.The volume of the cone would be The volume of a cylinder with the same dimensions would be the cylinder is 24 - 8 = 16 cubic inches greater.

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Find the equation of a line that passes the points (5, -9) and (0, -3)
kobusy [5.1K]

Answer:

y = -6/5x - 3

Step-by-step explanation:

Point Slope Form:  (y - y1) = m(x - x1)

<u>Step 1:  Find Slope</u>

m = \frac{y2-y1}{x2-x1}

m = \frac{-3 - (-9)}{0 - 5}

m = \frac{-3 + 9}{-5}

m = \frac{6}{-5}

m = \frac{-6}{5}

<u>Step 2:  Plug into Point Slope Form</u>

(y - (-3)) = -6/5(x - 0)

y + 3 - 3 = -6/5x - 3

y = -6/5x - 3

Answer:  y = -6/5x - 3

5 0
3 years ago
Read 2 more answers
Janeel has a 10-inch by 12-inch photograph. She wants to scan the photograph, then reduce the result
Vaselesa [24]

<u>Complete Question:</u>

Janeel has a 10 inch by 12 inch photograph. She wants to scan the photograph, then reduce the results by the same amount in each dimension to post on her Web site. Janeel wants the area of the image to be one eight of the original photograph. Write an equation to represent the area of the reduced image. Find the dimensions of the reduced image.

<u>Correct Answer:</u>

A) (10-x)(12-x)=15

B) Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

<u>Step-by-step explanation:</u>

a. Write an equation to represent the area of the reduced image.

Let the reduced dimensions is by x , So the new dimensions are

length=10-x\\breadth=12-x

According to question , Area of new image is :

⇒ Area = \frac{1}{8}Length(breadth)

⇒ Area = \frac{1}{8}(10)(12)

⇒ Area = 15

So the equation will be :

⇒ (10-x)(12-x)=15

b. Find the dimensions of the reduced image

Let's solve :  (10-x)(12-x)=15

⇒ 120-10x-12x+x^2=15

⇒ 120-22x+x^2=15

⇒ x^2-22x+105=0

By Quadratic formula :

⇒ x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

⇒ x = \frac{22 \pm8 }{2}

⇒ x = \frac{22 +8 }{2} , x = \frac{22 -8 }{2}

⇒ x = 15 , x =7

x = 15 is rejected ! as 15 > 10 ! Side can't be negative

⇒ x =7

Therefore, Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

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3 years ago
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Answer:

b

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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I’m 89% sure it’s d
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