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zloy xaker [14]
3 years ago
12

The diameter of a cone shaped is 4 in. Its height is 6 in. How much greater is the volume of a cylinder shaped container with th

e same diameter and height? Please show work
Mathematics
1 answer:
nasty-shy [4]3 years ago
5 0

The radius r used in below equations would equal 2in because it is half the given diameter of 4in.The volume of the cone would be The volume of a cylinder with the same dimensions would be the cylinder is 24 - 8 = 16 cubic inches greater.

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. If there are 20 girls in a class of 30 students, find out the percentage of boys in the class?​
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Answer:

10

Step-by-step explanation:

because there are 20 girls and 10 boys = 30

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2 years ago
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Give a example from everyday life of an angel that measures 90 degrees
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The corners of a door
The edge of a table
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3 years ago
An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
3 years ago
Solve the system of two linear inequalities graphically.
Sladkaya [172]

Answer:

See attachment

Step-by-step explanation:

Isolate y in the first inequality:

2x + 4y < -16\\4y < - 16 -2 x\\y < -4 -\frac{1}{2} x\\y < -\frac{x+8}{2} \\

Now, with both x and y inequalities found, graph it.

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2 years ago
Mrs. Hanson has a potato salad recipe that calls for 238 pounds of potatoes, but she wants to make 112 times as much as the reci
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Answer:

3 9/16 lbs

Step-by-step explanation:

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