The answer is definitely c
Answer: the population after 5 years is 10814
Step-by-step explanation:
The population growth of the deer is exponential. We would apply the formula for determining exponential growth which is expressed as
A = P(1 + r)^t
Where
A represents the population after t years.
n represents the period of growth
t represents the number of years.
P represents the initial population.
r represents rate of growth.
From the information given,
P = 10289
r = 1% = 1/100 = 0.01,
t = 5 years
Therefore,
A = 10289(1 + 0.01)^5
A = 10289(1.01)^5
A = 10814
Answer:
See below.
Step-by-step explanation:
Again, another great question!
This should be under physics, as it involves Work = Force * Distance. As Anne pushes the wheelbarrow with a force of 70 Newtons with respect to an angle of 50 degrees horizontal, the horizontal force is 70( cos 50 ). The distance over which the work is done is 25 meters, so work should be -
Work = ( 70( cos 50 ) )( 25 ),
Work = ( About ) 1124.87 Joules
<u><em>The work done when Anne pushes the wheelbarrow a distance of 25 meters, is 1124.87 Joules</em></u>
The value of the 3 in 6300 os 300 and it is ten times as many as the 3 in 530
